Answer:
82.416 g of KNO
₃ is needed to produce 510.0 mL of a 1.6 M KNO
₃ solution.
Explanation:
Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?
moles= 0.816
Being the molar mass of the elements:
- K: 39 g/mole
- N: 14 g/mole
- O: 16 g/mole
So the molar mass of the compound KNO₃ is:
KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole
Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?
mass= 82.416 grams
<u><em>82.416 g of KNO
₃ is needed to produce 510.0 mL of a 1.6 M KNO
₃ solution.</em></u>
Answer:
(1) conversion of mass to energy
Explanation:
Nuclear fission: In nuclear fission, an unstable atom splits into two or more smaller pieces that are more stable, and releases energy in the process. The fission process also releases extra neutrons, which can then split additional atoms, resulting in a chain reaction that releases a lot of energy.
It take 0.54 hours to deposit 6.36g of copper
<h3>Further explanation</h3>
Faraday's Law I
"The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis
W = e.i.t / 96500
e = equivalent = Ar / valence
i = current, A
t = time, s
W=6.36 g
e = 63.5 : 2 =31.75
i = 10 A
I would say D. Let me know if i am wrong.