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3 years ago

Why are cars manufactures exploring hydrogen fuel cell technology as a possiable replacement for gasoline burning engines

Chemistry

1 answer:

horsena [70]3 years ago

4 0

To possibly take down on the pollution we produce in the world

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Given the following reaction:

Semenov [28]

Answer:

The answer to your question is 0.35 moles of ZnCl₂

Explanation:

Data

moles of ZnCl₂ = ?

mass of Zn = 23 g

mass of CuCl₂ = excess

Balanced chemical reaction

Zn + CuCl₂ ⇒ ZnCl₂ + Cu

Process

1.- Convert the mass of Zn to moles

-Look for the atomic mass of Zn

Atomic mass = 65.4 g

-Convert the grams to moles

65.4 g -------------- 1 mol

23 g ---------------- x

x = (23 x 1)/65.4

x = 23 / 65.4

x = 0.35 moles of Zn

2.- Calculate the moles of ZnCl₂ using proportions and cross multiplication, and the coefficients of the balanced chemical reaction.

1 mol of Zn ---------------- 1 mol of ZnCl₂

0.35 moles of Zn -------- x

x = (0.35 x 1) / 1

x = 0.35 moles of ZnCl₂

7 0

3 years ago

Formula empirica del glutamato monosódico

Citrus2011 [14]

Answer:

C₅H₈NO₄Na

Explanation:

8 0

2 years ago

Given the following reaction: \ce{Cu + 2AgNO3 -> 2Ag + Cu(NO3)2}Cu+2AgNO3 2Ag+Cu(NOX 3 )X 2 How many moles of \ce{Ag}

Alexandra [31]

Answer:

0.252 mol

Explanation:

Given the following reaction:

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

How many moles of Ag will be produced from 16.0 g Cu, assuming AgNO3 is available in excess.

First, we write the balanced equation.

Cu + 2 AgNO₃ → 2 Ag + Cu(NO₃)₂

We can establish the following relations.

The molar mass of Cu is 63.55 g/mol.
The molar ratio of Cu to Ag is 1:1.

The moles of Ag produced from 16.0 g of Cu are:

$16.0gCu.\frac{1molCu}{63.55gCu} .\frac{1molAg}{1molCu} =0.252 molAg$

6 0

3 years ago

Read 2 more answers

What is the balanced chemical equation for the combustion of sulphur

nikitadnepr [17]

Answer:

S+O2⇒SO2

Explanation:

3 0

2 years ago

Read 2 more answers

5) Calculate the molality of 0.210 mol of KBr dissolved in 0.075kg pure water?

Margaret [11]

Answer:

$\boxed {\boxed {\sf 2.8 \ m }}$

Explanation:

The formula for molality is:

$m=\frac{moles \ of \ solute}{kg \ of \ solvent}$

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

$moles= 0.210 \ mol \\kilograms = 0.075 \ kg$

Substitute the values into the formula.

$m= \frac{ 0.210 \ mol }{0.075 \ kg}$

Divide.

$m= 2.8 \ mol/kg= 2.8 \ m$

The molality is 2.8 moles per kilogram

5 0

3 years ago