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4 years ago

How can an impurity in a flame test affect the results?

Chemistry

1 answer:

MA_775_DIABLO [31]4 years ago

7 0

Explanation:

If a sample is impure, it means it contains multiple substances, this means that when you test it in a flame test, it will come up with a mixed color meaning you wont be able to tell what ions are in the substance.

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Which chemical equation is unbalanced?

Travka [436]

Answer:

Sr + O2 → 2SrO would be an unbalanced equation.

Explanation:

There is only one Sr on the left, and two on the right.

7 0

3 years ago

Read 2 more answers

During the summer after your first year at Carnegie Mellon, you are lucky enough to get a job making coffee at Starbucks, but yo

Studentka2010 [4]

Answer:

The answer is "36.76 ml "

Explanation:

In the given question, Its basic understanding to also be hired seems to be that coffee heat = heat that the milk absorbs

The following relationship defines heat:

$\to q = m C_{p}( T_2 - T_1)$

Its updated equation is:

$\to q_{\ coffee} = - q_\ milk} \\\\ \to m_{\ milk} C_{p} (T_2 - T_1)_{\ coffee} = - m_{ \ milk} C_{p} (T_2 - T_1)_{\ milk} ..........(a)$

The following information is provided to you as per the question:

1) Milk and coffee have the same heat power

2) Difference in coffee temperature is:

$\to (T_2 - T_1)_{\ coffee} = 75.0^{\circ} \ \ C-85.0^{\circ} \ \ C$

$= -10.0 ^{\circ} \ \ C$

3) The difference in milk temperature:

$\to (T_2 - T_1)_{ \ milk} = 75.0^{\circ} \ \ C- 7.0^{\circ} \ \ C$

$= 68.0 ^{\circ} \ \ C$

4) Milk and coffee density are equal therefore, weight and volume are equal and have same ratio, that can be shown as follows:

$\to \ Density (\rho) =\frac{ \ Mass (m)}{ \ Volume (V)} \\\\\to m= V \times \rho \\\\$

$\to m_{\ coffee} \times (T_2 - T_1)_{ \ coffee}= -m_{\ milk} \times (T_2 - T_1)_{milk} \\\\\to V_{\ coffee} \times \rho_{\ coffee} \times (T_2 - T_1)_{\ coffee} = - V_{\ milk} \times \rho_{\ milk} \times (T_2 - T_1)_{\ milk} \\\\\to V_{\ coffee} \times (T_2 - T_1)_{\ coffee} = - V_{\ milk} \times (T_2 - T_1)_{\ milk}.............(b)$

by replace the equation values (b) for calculating milk volumes as shown as follows:

$\to V_{\ coffee} \times (T_2 - T_1)_{\ coffee} = - V_{\ milk} \times (T_2 - T_1)_{\ milk}\\\\\to 250 ml \times (-10 .0^{\circ} \ \ C) = - V_{\ milk} \times (68.0^{\circ} \ \ C)\\\\\to V_{\ milk}= \frac{250 ml \times (-10 .0^{\circ} \ \ C) }{- (68.0^{\circ} \ \ C)}$

$= 36.76 \ ml$

4 0

3 years ago

determine the final temperature of a 10-0-g aluminum block originally at 25.0°C if you apply 435 joules of energy to it

mihalych1998 [28]

Energy = Mass * heat capacity * temperature change so,
The energy added is 435 J and the temperature has to increase since the energy is added.

435 J = 10.0 g * 0.89 J/gC * temperature change 

Temperature change = 48.9 C 

The initial temperature is 25.0 C, the final temperature is 25.0 C + 48.9 C = 73.9 C.

5 0

4 years ago

1375 J of heat energy are added to a 50.0 g sample of copper, which increases temperature from 22.8 C to 94.2 C. Calculate the s

sergeinik [125]

Answer:

0.385 J/g°C

Explanation:

Using the following formula, the specific heat of an elemental substance can be calculated:

Q = m × c × ∆T

Where;

Q = quantity of heat (J)

m = mass (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Based on the given information, Q = 1375J, m = 50g, initial temperature = 22.8°C, final temperature = 94.2°C, c =?

Q = m × c × ∆T

1375 = 50 × c × (94.2 - 22.8°C)

1375 = 50 × c × 71.4

1375 = 3570c

c = 1375/3570

c = 0.3851

c = 0.385 J/g°C

3 0

3 years ago

A student prepares a solution of sodium chloride by dissolving 116.9 g of NaCl into enough water to make 1.00 L of solution. How

sertanlavr [38]

Answer: The molarity of the solution is 2.00 M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L = 1.00 L

moles of solute = $\frac{\text {given mass}}{\text {molar mass}}=\frac{116.9g}{58.5g/mol}=2.00moles$

$Molarity=\frac{2.00mol}{1.00L}=2.00M$

Thus the molarity of the solution is 2.00 M

8 0

4 years ago