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3 years ago

HELPP determine the unit rate if you work and earn 171.00 in 12 hours. what is the dollar per hour you make???

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

5 0

Answer:

hi glad to help so what you do is basically divide 171 by 12 and you get 14.25 so the unit rate is 14.25 per hour hope i helped plz can i have brainliest

Step-by-step explanation:

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Two congruent 30-60-90 triangles are placed,as shown,so that they overlap partly and their hypotenuses coincide. If the hypotenu

Ede4ka [16]

Answer: The area common to both triangle is 31.77 sq. cm.

Step-by-step explanation:

Since we have given that

30-60-90 triangles are placed.

So, the ratio of sides would be

$1:\sqrt{3}:2$

Since Hypotenuse = 12 cm

So, it becomes,

$2x=12\\\\x=\dfrac{12}{2}=6$

So, Base would be

$x=6\ cm$

and Perpendicular would be

$\sqrt{3}x=6\sqrt{3}$

So, Area common to the both triangles would be

$\dfrac{1}{2}\times base\times height\\\\=\dfrac{1}{2}\times 6\times 6\sqrt{3}\\\\=18\sqrt{3}\\\\=31.177$

Hence, the area common to both triangle is 31.77 sq. cm.

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3 years ago

Solve the following equation 4=-3y-2

Mamont248 [21]

Answer:

y = -2

Step-by-step explanation:

Move all the unknown no. to one side:

4 + 2 = -3y

-3y = 6

Solve the equation:

y = -2

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3 years ago

What is the range of the function f(x) = -2(6^x) + 3?

Naddika [18.5K]

Answer:

(-∞,3)

Explanation:

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3 years ago

Read 2 more answers

Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule

Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

a) What is the approximate percentage of men between 169 and 183 cm?

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

$\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183$

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

b) Between which 2 heights would 95% of men fall?

This corresponds to ±2 standard deviations off the mean.

$\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190$

95% of the men will fall between 162 cm and 190 cm.

c) Is it unusual for a man to be more than 197 cm tall?

The number of standard deviations of distance from the mean is

$n=(197-176)/7=3$

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

3 0

3 years ago

( simultaneous equations)

daser333 [38]

Answer:

See method below.

Step-by-step explanation:

m/n + n/3 = 2

2/m + n = 4

First eliminate the fractions by multiplying the first equation by 3n:-

3m + n^2 = 6n...........(1)

and the second equation by m:-

2 + mn = 4m..............(2)

Now we solve using substitution:-

From equation (2):-

4m - mn = 2

m = 2 / (4 - n)

Now substitute for m in equation (1):-

6/ (4 - n) + n^2 = 6n

6 + n^2(4 - n) = 6n(4 - n)

6 + 4n^2 - n^3 = 24n - 6n^2

n^3 - 10n^2 + 24n - 6 = 0

This will not factor so we could solve this using graphical software.

To find the values of the variable m we substitute the found values of n into one of the original equations and solve for m.

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3 years ago