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Norma-Jean [14]
3 years ago
6

The _______ functional group can always be found in a carbohydrate molecule.

Biology
2 answers:
frutty [35]3 years ago
5 0

Explanation:

The hydroxyl functional group can always be found in a carbohydrate molecule.

Answer is hydroxyl - b

julia-pushkina [17]3 years ago
5 0

Hello There!

YOUR ANSWER IS "B"

The hydroxyl functional group can always be found in a carbohydrate molecule.

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In which part of a cell does transcription take place
nadezda [96]
Will take place in the nucleus where the DNA is located
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3 years ago
Based on the picture below, answer the following T/F questions. Explain your answer. a. The two chromosomes on the left (#1) are
STatiana [176]

Answer:

a) False.

b) True.

c) False.

d) True.

e) False.

f) True

g) True.

Explanation:

a) The main characteristic of homologous chromosomes is that they have an equal size. There is a difference in size on both chromosomes.

b) In number one, two chromosomes are homologous. In number two also two chromosomes are homologous. On the other hand, the chromosomes at number one and two are different. Each chromosome has two sister chromatids.

c) A DNA molecule has a double helix, that is, two chains. When a DNA chain is broken and a chromatide has a DNA chain, then two chromatids make up a chromosome and a DNA chain, in this way there are eight dsDNA molecules

d) If each chromosome contains a centromere, therefore, there are four centromeres on all four chromosomes.

e) If a chromosome contains four telomeres, therefore there will be sixteen telomeres.

f) The function of cohesin is to regulate the separation of chromatids in the cell division process. When DNA replication is complete, the DNA compacts and condenses to form mitotic chromosomes.

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3 years ago
Whole animal cloning produces a new offspring that is identical to
Oduvanchick [21]
The animal it gave birth to 
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4 years ago
Barred feather pattern is a Z-linked dominant trait in chickens. What offspring would you expect from (a) the cross of a barred
Bezzdna [24]

Answer:

Let the "barred" allele be caller B and the "non-white" allele b. Since chickens use chromosomes Z  and W to determine sex, hens would have chromosomes ZW, and roosters would have chromosomes ZZ. A Z-linked gene is represented as a superscript on the Z chromosome, Z^{B} for the dominant allele and Z^{b} for the ressesive allele.

A barred hen would have a copy of B on its Z chromosome, a non-barred rooster would have both copies of b on both Z chromosomes. Using Punnet squares to represent the crosses we get the following cases:

\begin{center}\begin{tabular}{ |c|c|c|c| }\ & Z^{B} & W \\ \ Z^{b} & Z^{B}Z^{b} & Z^{b}W \\ \ Z^{b} & Z^{B}Z^{b} & Z^{b}W \\ \end{tabular}\end{center}

That is a ratio of two barred heterozygote roosters to two non-barred hens. Crossing them we get:

\begin{center}\begin{tabular}{ |c|c|c|c| }\ & Z^{b} & W \\ \ Z^{B} & Z^{B}Z^{b} & Z^{B}W \\ \ Z^{b} & Z^{b}Z^{b} & Z^{b}W \\ \end{tabular}\end{center}

That is a ratio of one barred heterozygote rooster to one barred hen to one non-barred rooster to one non barred hen.

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3 years ago
Explain why lamarckism is currently not a widely accepted theory​
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Answer:

Its not really taught in schools that much.

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