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3 years ago

5

The cost for shipping a package that weight x pounds from Boise to Los Angeles is shown at the right . How much more does Shippi

ng Central charge that Globe Delivery ?

1 answer:

sergij07 [2.7K]3 years ago

4 0

4x pounds from Boise to Los Angeles

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Answer all parts of number 1 thank you.

Scorpion4ik [409]

Hi!

1.)

a:A u B=

$(1.0. - 5. \frac{1}{2} .e)$

(The same elements are written once.)

b:A u C

$(1.0 - 5. \frac{1}{2} .2)$

c:B u C

$( - 5 .1.e.0.2)$

Note:I used dots to mean commas .

Good work!

7 0

2 years ago

Evaluate the expression when y = - 3.<br> - 7y2

yuradex [85]

So what you do for this one if you plug it in.
-7y2. So you have -7(-3)^2 which is -7(9) which is -63. So your answer is -63. Hope this helps!!!

4 0

3 years ago

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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

marishachu [46]

Answer:

Thus, the two root of the given quadratic equation $x^2-6=-x$ is 2 and -3 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2-6=-x$

This can be written as , $x^2+x-6=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = 1 , c = -6

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(1)\pm\sqrt{(1)^2-4\cdot 1 \cdot (-6)}}{2 \cdot 1}$

$\Rightarrow x=\frac{-1\pm\sqrt{25}}{2}$

$\Rightarrow x=\frac{-1\pm 5}{2}$

$\Rightarrow x_1=\frac{-1+5}{2}$ and $\Rightarrow x_2=\frac{-1-5}{2}$

$\Rightarrow x_1=\frac{4}{2}$ and $\Rightarrow x_2=\frac{-6}{2}$

$\Rightarrow x_1=2$ and $\Rightarrow x_2=-3$

Thus, the two root of the given quadratic equation $x^2-6=-x$ is 2 and -3 .

7 0

3 years ago

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The hanger image below represents a balanced equation.

Allushta [10]

Answer:

2x =3

The hanger image given in the figure represents balanced equation.

Then we have to write an equation to represent the image.

In balanced form left side = right side

x + x = 1 + 1 + 1

2x = 3

5 0

2 years ago

To evaluate an expression with variables: 1. Substitute the values for the variables. 2. Identify grouping symbols, beginning wi

Eduardwww [97]

Evaluate the expression using x = –1 and y=3.

$(6x^4y^3)$

1. Substitute the values for the variables.

we plug in -1 for x and 3 for y

$(6x^4y^3)$

$(6(-1)^4(3)^3)$

2. Identify grouping symbols, beginning with the innermost symbols.

$(6*(-1)^4*(3)^3)$

We take exponent and then we multiply

3. Determine and apply the rules of exponents to simplify

$(6*(-1)^4*(3)^3)$

(-1)^4 = -1 * -1 * -1 * -1 = 1

(3)^3 = 3*3*3= 27

$(6*(1)*(27))$

4. Evaluate.

$(6*(1)*(27))$

162

The value of the expression is 162

6 0

3 years ago

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