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Vlada [557]
3 years ago
14

Helppppppppppppppppppp

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
7 0
Hello C is the answer
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Assume that the heights of bookcases are normally distributed. A random sample of 16 bookcases in one company have a mean height
ipn [44]

Answer: 1.1 and 3.1

Step-by-step explanation:

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3 years ago
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A line has a slope of -1/4 and passes through point (-5/4, 1) What is the equation of the line?
Vedmedyk [2.9K]
The line of the equation would be y = -1/4x + 11/16.

In order to find that, we'll put the ordered pair and the slope into slope intercept form. Then we can solve for the intercept. 

y = mx + b
1 = -1/4(-5/4) + b
1 = 5/16 + b
11/16 = b

So then we put that in the equation with slope for the final equation. 
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3 years ago
Alexis is making bread dough.The recipe requires 3/4 cup of flour and 1 2/5 teaspoon of salt. To maintain the ratio,how much sal
tekilochka [14]

Answer:

16/5 teaspoons

Step-by-step explanation:

1/4 cups of flour uses 4/15 teaspoon so 4/15 x 4 is 16/5

7 0
3 years ago
Solve the formula for R.
kati45 [8]

The Last Answer

R = PV/nT

6 0
3 years ago
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D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
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