Answer:
![g(x) = 6](https://tex.z-dn.net/?f=g%28x%29%20%3D%206)
Step-by-step explanation:
Begin with substuting the x variable with -2, we do this because the question has listed the value of x already.
Using the value of x, -2 we determine g(x).
g(x) = -2^2 + 2
Above is what the equation would look as, after you input the value of -2.
Using pemdas, (parantheses, exponents, multiplication, division, addition, subtraction) solve the equation.
-2^2 = 4
Think of it as -2 * -2, which is why -2^2 is 4.
Add 4 +2.
4 + 2 = 6.
Therefore, the value of g(x) = 6
Answer:
what do you want to find
Step-by-step explanation:
I hope this helps you
Surface Area= 2.pi.r.h+2.pi.r^2
Surface Area =2.pi.3/2.10+2.pi. (3/2)^2
Surface Area =30pi+4,5.pi
Surface Area =34,5.pi
![\begin{gathered} a=41.50 \\ b=35.78 \\ B=40.76\text{ \degree} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%3D41.50%20%5C%5C%20b%3D35.78%20%5C%5C%20B%3D40.76%5Ctext%7B%20%5Cdegree%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Explanation
Step 1
a) let
![\begin{gathered} A=49.23\text{ \degree} \\ c=54.8\text{ \degree} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D49.23%5Ctext%7B%20%5Cdegree%7D%20%5C%5C%20c%3D54.8%5Ctext%7B%20%5Cdegree%7D%20%5Cend%7Bgathered%7D)
b) b value
to find the measure of side b we can use cosine function
![\begin{gathered} cos\theta=\frac{adjacent\text{ side}}{hypotenuse} \\ replace \\ cos\text{ 49.23=}\frac{b}{54.8} \\ b=54.8*cos49.23 \\ b=35.78 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20cos%5Ctheta%3D%5Cfrac%7Badjacent%5Ctext%7B%20side%7D%7D%7Bhypotenuse%7D%20%5C%5C%20replace%20%5C%5C%20cos%5Ctext%7B%2049.23%3D%7D%5Cfrac%7Bb%7D%7B54.8%7D%20%5C%5C%20b%3D54.8%2Acos49.23%20%5C%5C%20b%3D35.78%20%5Cend%7Bgathered%7D)
c) angle B
to find the measure of Angle B we can use sine function
![\begin{gathered} sin\theta=\frac{opposite\text{ side}}{hypotenuse} \\ replace \\ sin\text{ B=}\frac{35.78}{54.8} \\ sin\text{ B= 0.65}\Rightarrow inverse\text{ function to isolate B} \\ B=\sin^{-1}(0.65) \\ B=40.76 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20sin%5Ctheta%3D%5Cfrac%7Bopposite%5Ctext%7B%20%20side%7D%7D%7Bhypotenuse%7D%20%5C%5C%20replace%20%5C%5C%20sin%5Ctext%7B%20B%3D%7D%5Cfrac%7B35.78%7D%7B54.8%7D%20%5C%5C%20sin%5Ctext%7B%20B%3D%200.65%7D%5CRightarrow%20inverse%5Ctext%7B%20function%20to%20isolate%20B%7D%20%5C%5C%20B%3D%5Csin%5E%7B-1%7D%280.65%29%20%5C%5C%20B%3D40.76%20%5Cend%7Bgathered%7D)
d) side a
![\begin{gathered} sin\theta=\frac{opposite\text{ side}}{hypotenuse} \\ sin\text{ A=}\frac{a}{c}=\frac{\placeholder{⬚}}{\placeholder{⬚}} \\ sin\text{ 49.23=}\frac{a}{54.8} \\ multiply\text{ both sides by 54.8} \\ 54.8s\imaginaryI n\text{49.23=}\frac{a}{54.8}*54.8 \\ 41.50=a \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20sin%5Ctheta%3D%5Cfrac%7Bopposite%5Ctext%7B%20side%7D%7D%7Bhypotenuse%7D%20%5C%5C%20sin%5Ctext%7B%20A%3D%7D%5Cfrac%7Ba%7D%7Bc%7D%3D%5Cfrac%7B%5Cplaceholder%7B%E2%AC%9A%7D%7D%7B%5Cplaceholder%7B%E2%AC%9A%7D%7D%20%5C%5C%20sin%5Ctext%7B%2049.23%3D%7D%5Cfrac%7Ba%7D%7B54.8%7D%20%5C%5C%20multiply%5Ctext%7B%20both%20sides%20by%2054.8%7D%20%5C%5C%2054.8s%5CimaginaryI%20n%5Ctext%7B49.23%3D%7D%5Cfrac%7Ba%7D%7B54.8%7D%2A54.8%20%5C%5C%2041.50%3Da%20%5Cend%7Bgathered%7D)
so, the answer is
![\begin{gathered} a=41.50 \\ b=35.78 \\ B=40.76\text{ \degree} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20a%3D41.50%20%5C%5C%20b%3D35.78%20%5C%5C%20B%3D40.76%5Ctext%7B%20%5Cdegree%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
I hope this helps you