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3 years ago

A wave is moving toward shore with a velocity of 5.0 m/s. If the frequency is 2.5 Hz, what is the wavelength?

Physics

1 answer:

DochEvi [55]3 years ago

5 0

Wavelength= velocity/frequency
5/2.5=2

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23. If a jogger runs 100 meters west and then turns around and runs 30 meters east. What

marshall27 [118]

Answer:

Explanation:

if he goes to the west, the east is opposite so 100-30

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3 years ago

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If an airplane undergoes a displace-

PIT_PIT [208]

The formula for velocity is distance divided by time, or d/t. The distance is 500 km and the time is 1.2 hours. 500/1.2 is 416.6 km/hr.

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3 years ago

7. Two bikes travelling in the same direction move at a speed of 30 km/hr. The bikes are separated by a distance of 5 km. What w

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Answer:

Explanation:

Call the bike on the right A

Call the bike on the left B

The car begins it's time when it passes A

4 minutes later, it passes B.

But B has moved in 4 minutes and that is the key to the problem.

How far has B moved.

t = 4 minutes = 4/60 hours = 1/15 of an hour.

d = ?

rate = 30 km / hr

d = r * t

d = 30 km/hr * 1/15 hours = 2 km

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d = 3 km

r = ?

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4 years ago

The eiffel tower has a mass of 7.3 million kilograms and a height of 324 meters. its base is square with a side length of 125 me

uranmaximum [27]

Since the tower base is square with a side length of 125 m,

Therefore,

$(125\ m)^2+ (125\ m)^2=31250 m^2$

Square root of 31250 = 176.776953 (Diameter) , so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.

The volume of cylinder,

$=\pi r^2h=3.14(88.38834765 m)^2\times 324 m =7948168.803\ m^3$

Thus, the mass of the air in the cylinder,

$=1.225\ kg/m^3 \times 7948168.803\ m^3=9736506.78\ kg$

Hence, the mass of the air in the cylinder is this more than the mass of the tower.

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3 years ago

In Trial II, the same spring is used as in Trial I. Let us use this information to find the suspended mass in Trial II. Use 0.51

Masteriza [31]

Answer:

$M_2=0.79kg$

Explanation:

From the question we are told that:

Period $T=0.517s$

Trial 1

Spring constant $\mu=117N/m$

Period $T_1=0.37$

Mass $m=0.400kg$

Trial 2

Period $T_2=0.52$

Generally the equation for Spring Constant is mathematically given by

\mu=\frac{4 \pi^2 M}{T^2}

Since

$\mu _1=\mu_2$

Therefore

$\frac{4 \pi^2 M_1}{T_1^2}=\frac{4 \pi^2 M_2}{T_2^2}$

$M_2=M_1*(\frac{T_2}{T_1})^2$

$M_2=0.400*(\frac{0.52}{0.37}})^2$

$M_2=0.79kg$

5 0

3 years ago