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Vikentia [17]
3 years ago
14

If their were two dogs and 1 cat who would win hint: The Car

Physics
2 answers:
bixtya [17]3 years ago
8 0
The car that hit the dog and cat would win
Naya [18.7K]3 years ago
5 0

Answer: No one.

Explanation: When a dog sees a car, it is most likely to chase after it. If the dogs run away, that leaves the cat. The cat will get antsy, and leave. Therefore, no one wins. Also, don't encourage animal fighting.

*There, not their. Their is possesive.*

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Answer:

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Explanation:

  • When at the bottom of the dip, the only force that keeps the car in the circular trajectory, is the centripetal force.
  • This force is not a new force, is just the net force aiming to the center of the circle.
  • In this case, is just the difference between the normal force (always perpendicular to the surface, pointing upward) and the force that gravity exerts on the car (which is known as the weight), pointing downward.
  • So, we can write the following expression:

       F_{cent} = F_{n} - F_{g}  (1)

  • It can be showed that the centripetal force is related to the speed by the following expression:
  • F_{cent} = m*\frac{v^{2}}{r} (2)
  • The normal force, it is called the apparent weight, because it would be the weight as measured by a scale.
  • Replacing (2) in (1), and solving for Fn, we get:

       F_{n} = m*\frac{v^{2} }{r} + m*g (3)

  • Now, we need to find the value of v that makes Fn, exactly 15% more than the weight m*g, so we can write the following equation:

      F_{n} = 1.15*F_{g} = m*\frac{v^{2}}{r} +F_{g}  (4)

  • Replacing Fg by its value, simplifying, and solving for v, we get:

       v = \sqrt{0.15*g*r} = \sqrt{9.8 m/s2*0.15*150m} = 14.85 m/s (5)

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