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seraphim [82]
3 years ago
13

What was the runoff from precipitation on the property for areas with vegetation and roofed or paved areas over the past four mo

nths? What percent of total precipitation ran off of the property? Include data tables in your answer. Would you expect this percentage to be the same for the properties of other students in the class? Why or why not? What factors decide the percentage of runoff?
Physics
1 answer:
puteri [66]3 years ago
5 0

Answer:

Higher percentage of runoff water is absorbed by the vegetation whereas 100 % of water runoff on the roofed area.

Explanation:

Higher percentage of runoff water is absorbed by the vegetation and very little amount of runoff water is received on the end of vegetative cover while on the other hand, 100 percent of precipitation water runoff on the surface of roofed or paved area because no water is absorbed by the roof due to its solid surface. The percentage of runoff depends on the factors such as rainfall intensity, slope, soil water storage capacity, and infiltration rate.

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A clay pot at room temperature is placed in a kiln, and the pot\'s temperature doubles. how much more heat per second is the pot
xeze [42]

Answer:

16

Explanation:

If we treat the pot as a black body, then:

q = σ T⁴ A,

where q is the heat per second radiated,

σ is the Stefan-Boltzmann Constant,

T is the absolute temperature,

and A is the surface area.

If the absolute temperature doubles, then q increases by a factor of 2⁴ = 16.

7 0
3 years ago
A basketball player standing up with the hoop launches the ball straight up with an initial velocity of v_o = 3.75 m/s from 2.5
denis23 [38]

Answer:

a) The maximum height the ball will achieve above the launch point is 0.2 m.

b) The minimum velocity with which the ball must be launched is 4.43 m/s or 0.174 in/ms.

Explanation:

a)

For the height reached, we use 3rd equation of motion:

2gh = Vf² - Vo²

Here,

Vo = 3.75 m/s

Vf =  0m/s, since ball stops at the highest point

g = -9.8 m/s² (negative sign for upward motion)

h = maximum height reached by ball

therefore, eqn becomes:

2(-9.8m/s²)(h) = (0 m/s)² - (3.75 m/s²)²

<u>h = 0.2 m</u>

b)

To find out the initial speed to reach the hoop at height of 3.5 m, we again use 3rd eqn. of motion with h= 3.5 m - 2.5m = 1 m (taking launch point as reference), and Vo as unknown:

2(-9.8m/s²)(1 m) = (0 m/s)² - (Vo)²

(Vo)² = 19.6 m²/s²

Vo = √19.6 m²/s²

<u>Vo = 4.43 m/s</u>

Vo = (4.43 m/s)(1 s/1000 ms)(39.37 in/1 m)

<u>Vo = 0.174 in/ms</u>

<u />

6 0
3 years ago
Help please…………………,,,,,
Sever21 [200]

Answer:

*insert smrt science stuff here*

Explanation:

am smrt

5 0
3 years ago
Two marbles (m = 0.050 kg each) moving on a table TOWARDS each other with the speed of 0.3 m/s collide, and start moving away fr
snow_tiger [21]

Answer:

V1 = ____0.3______ m/s, V2 = ____-0.3______ m/s,

p1 = ____0.015______ kg m/s, p2 = ___-0.015_______ kg m/s,

ptotal = _0___________ kg m/s

Explanation:

Taking the marble ball that moves from right to left as Marble 1 and the one that moves from left to right as Marble 2. We take direction from left to right as negative and from right to left as positive. Therefore, velocity of marble 1 will be +0.3 m/s while velocity of marble 2 will be -0.3 m/s. The mass of marble 1, m2 0.05 Kg and same to marble 2, m2=0.05 Kg

Momentum is product of mass and velocity hence using p to represent momentum

P1=0.05*0.3=0.015 Kg m/s

P2=0.05*-0.3=-0.015 Kg m/s

V1=0.3 m/s, V2=-0.3 m/s

The total momentum before collision will be the sum of P1 and P2 hence 0.015 Kg m/s+-0.015 Kg m/s=0

Ptotal=0 Kg m/s

7 0
3 years ago
Please help &amp; actually answer thank you :)
Katarina [22]

Answer:

0.5x35=17.5

Explanation:

You throw 0.5 kg the ball leaves your hand with

A speed of 35

4 0
3 years ago
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