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kicyunya [14]
3 years ago
6

Solve 6 sin((π/5)x)=5 for the four smallest positive solutions

Mathematics
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

1.568, 3.432, 11.568, 13.432

Step-by-step explanation:

Divide equation 6\sin\left(\dfrac{\pi }{5}x\right)=5 by 6:

\sin\left(\dfrac{\pi }{5}x\right)=\dfrac{5}{6}.

Then

\dfrac{\pi }{5}x=(-1)^k\arcsin\left(\dfrac{5}{6}\right)+\pi k,\ k\in Z,

x=(-1)^k\dfrac{5}{\pi }\arcsin\left(\dfrac{5}{6}\right)+5k,\ k\in Z.

Since \arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},

four smallest positive solutions are

1. \dfrac{5}{3.2}\approx 1.568,\ k=0;

2. \dfrac{-5}{3.2}+5\approx 3.432,\ k=1;

3. \dfrac{5}{3.2}+10\approx 11.568,\ k=2;

4. \dfrac{-5}{3.2}+15\approx 13.432,\ k=3.

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