Answer:
Specific Learning Outcomes:
Solve problems that involve finding powers of a number
Description of mathematics:
In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.
Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further, these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …
The same is true of the digit in the tens place.
Answer:
A
Step-by-step explanation:
I didn't learn jrf, but I believe that it is the amount of females that watch action movies divided by the total amount of females.
Amount of females who watch action movies= 99
Total females= 250
So, A seems correct.
Answer:
Step-by-step explanation:
let the speed of one plane=x
speed of other plane=x+80
time=4 hrs
then 4x+4(x+80)=3800
4x+4x+320=3800
8x=3800-320
or 8x=3480
x=435
speed of one plane=435 m/h
speed of other plane=435+80=515 m/h
2.
Let he walks x hrs
then he take a taxi for 2-x hrs
4x+(2-x)50=31
4x+100-50x=31
-46x=-69

so he walks 3/2 hrs=1.5 hrs
travels by taxi=2-1.5=0.5 hrs
distance traveled by taxi=0.5×50=25 miles
You have to do 3.14 times the diameter of the circle.
Answer:
20 comic books
Step-by-step explanation:
Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.
Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

Therefore, Jared has 20 comic books.
<em>I hope this helps! Please let me know if you have any further questions :)</em>