All categories

3 years ago

Can 39/121 be simplified and if so what is it??

Mathematics

1 answer:

BabaBlast [244]3 years ago

3 0

Hi there!

Unfortunately, the beautiful fraction you've given us is simplified enough, and it cannot go any lower than what it is. So basically, you're left with $\frac{39}{121}$

Hope this helps!

Message me if you need anything else! I'd be happy to help! :D

You might be interested in

How to regroup 378x6. pls help mev

olga55 [171]

It is 2,268!!! Thts the answer

7 0

3 years ago

Use point-slope form to write the equation of a line that passes through the point

Ymorist [56]

Answer:

y= -2x-22.

Step-by-step explanation:

1) the slope-interception common form is y=s*x+i, where 's' and 'i' are the slope and interception, unknown numbers;

2) if x₁= -3; y₁= -16, and s=-2, then the equation of the required line can be written in the point-interception form y-y₁=s(x-x₁); ⇔ y+16= -2(x+3);

3) the required equation in slope-interception form is:

y+16= -2x-6; ⇒ y= -2x-22.

note, the provided solution is not the only and shortest way.

5 0

2 years ago

A model scale is 1 cm = 8m.<br> If the actual object is 40 meters, the model is<br> ____ cm long.

Dovator [93]

Answer:

Mmmmmmmmmmmmm.............

Step-by-step explanation:

MI no sabo amigo perdon

8 0

3 years ago

Read 2 more answers

A) Two angles are adjacent if their measures add up to 90°.

slavikrds [6]

Answer:

A) False

B) False

Step-by-step explanation:

A. Two angles whose measures add up to 90° are said to be complementary, while two angles are adjacent when formed beside each other. So, adjacent angles might be complementary or supplementary. Thus, the answer to the first part of the question is false.

B. When two angles share a side, they are said to be adjacent to each other. But supplementary angles add up to $180^{o}$ . Since adjacent angles might be complementary or supplementary, then the answer to the second part of the question is false.

4 0

3 years ago

Resolve into partial fractions 7-5x/2x^2+x-1

Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\$

To find:

partial fractions=?

Solution:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\$

putting $x=-1$

$\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\$

putting $x= \frac{1}{2}$

$\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2} \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\$

So, the final answer is " $\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\$ ".

Learn more:

brainly.com/question/22286068

3 0

3 years ago