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Luba_88 [7]
3 years ago
8

Please help 15 points

Mathematics
2 answers:
daser333 [38]3 years ago
3 0

Answer:

  1. x- + 10 y- +4
  2. not proportional

Step-by-step explanation:

i think the 1st one is wrong but hope this helps!

seropon [69]3 years ago
3 0
I think the second one is non portional
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Find the slope between the points. (4,-2) and (8,5)
aksik [14]
Slope = m

Equation to find slope is:

m = (y2 - y1) / (x2 - x1)

2 points:
(4,-2) 4 = x1 and -2 = y1
(8,5) 8 = x2 and 5 = y2

So...

m = (y2 - y1) / (x2 - x1)

m = (5 - (-2)) / (8 - 4)

m = 7 / 4 or 1.75

Therefore, the slope of the line is 7/4 OR 1.75.

3 0
3 years ago
A new truck costs $32,000 if the truck is worth 24,500 after three years write an explicit formula for the value of the car afte
Debora [2.8K]

Answer:

Step-by-step explanation:

depreciation for three years = 32000 - 24500 = $ 7500

depreciation per year = 7500/3 = $ 2500

depreciation % = (2500/32000)*100 = 7.81%

Value of truck after n years = 32000 * (7.81%)*n

8 0
3 years ago
Really struggling on this
navik [9.2K]
Angle 4 would be 77degrees because angle two is vertical to angle four.

Angle 3 and Angle 1 are equal because they are vertical to each other.

You would subtract 180 (degrees) minus 77 (degrees) and get 103 (degrees).

So Angle 3 and Angle 1 would both be 103 degrees.

You would get 180 degrees from the line.

5 0
2 years ago
A retail store sells two types of shoes, sneakers and sandals. The store owner pays $8 for the sneakers and $14 for the sandals.
soldier1979 [14.2K]

Answer:

134 sneakers and 66 sandals

Step-by-step explanation:

Sneakers= x, sandals= y

Profit rate:

  • sneakers: (10-2)/8= 25%
  • sandals: (17-14)/14= 21.4%

Sneakers are more profitable, so it should be maximized.

Cost:

8x+14y≤2000

x+y≤200

if we assume the maximum of 200 shoes stocked, then:

x= 200-y

8(200-y)+14y ≤ 2000

1600 - 8y +14y ≤ 2000

6y≤400

y≤66 and x=134 is the best option

3 0
3 years ago
Please help me, i'm trying to graduate!!!
Svet_ta [14]
If you use this equation then you say that the ground is h=0 and solve as a quadratic.
The quadratic formula is (-b±<span>√(b^2-4ac))/2a when an equation is in the form ax^2 + bx + c
So the equation you have been given would be -16t^2-15t-151 = 0
This equation has no real roots which leads me to believe it is incorrect.
This is probably where your difficulty is coming from, it's a mistake.

The equation is formed from S=ut+(1/2)at^2+(So) where (So) is the initial height and S is the height that you want to find.
In this case you want S = 0.
If the initial height is +151 and the initial velocity and acceleration are downwards (negative) and the initial velocity (u) is -15 and the initial acceleration is -32 then you get the equation S=-15t-16t^2+151

Solving this using the quadratic formula gives you t = 2.64 or t = -3.58
Obviously -3.58s can't be the answer so you're left with 2.64 seconds.

Hope this makes sense.
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3 0
3 years ago
Read 2 more answers
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