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Katen [24]
4 years ago
7

a driver was fined $20.00 plus $4.00 for every mile per hour over the speed limit of 55 mph. is the fine was $76, how fast was t

he driver going
Mathematics
1 answer:
Ksenya-84 [330]4 years ago
3 0
20+4x=76  subtract 20 from both sides

4x=56  divide both sides by 4

x=14

So he was driving at 55+14=69 mph
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Plz help <br><br> im helping my brother <br><br> :)
Tju [1.3M]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
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In the figure to the right, if AC = 15 and BC = 12, what is the radius?
Andrew [12]

Answer:

The radius is 9.0 units

Step-by-step explanation:

we know that

In the right triangle of the figure ABC

Applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

15^2=AB^2+12^2

solve for AB

AB^2=15^2-12^2\\AB^2=81\\AB=9\ units

Remember the the side AB of right triangle represent the radius of the circle

therefore

The radius is 9.0 units

6 0
3 years ago
What number needs to be added to 4 and 7 so that the ratio of
il63 [147K]

Answer:

a.

Step-by-step explanation:

4 0
3 years ago
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An object falls 9 meters during the first second, another 27 meters during the second second, and then 81 meters more during the
marishachu [46]
360 meters is the answer as 9 meter in 1st second ,27 meter in 2nd and 81 in 3rd it is in a series of geometric progression ...of 9,27,81 in which 9*3 =27,27*3=81 so next number will be 81*3=243 total distance moved in 4 seconds is 243+81+27+9=360 meters

4 0
3 years ago
Write the relation as a set of on rdered pai
kirill115 [55]

The relation as a set of ordered pairs is d. {(–2, 1), (0, -1), (2, -3)}.

Step-by-step explanation:

Step 1:

First, we plot the three points on the given graph.

The coordinates are given in the following form (x coordinate, y coordinate) where the symbol of the coordinates depends on the quadrant on which the point lies.

For the first quadrant, both x and y values are positive.

For the second quadrant, the x value is negative but the y value is positive.

For the third quadrant, both the values of x and y are negative.

For the fourth quadrant, the x value is positive but the y value is negative.

Step 2:

The first point has an x value of 2 and a y value of 1 since it is in the second quadrant, the coordinates are (-2, 1).

The second point has an x value of 0 and a y value of 1 since it is in the third or fourth quadrant, the coordinates are (0, -1).

The third point has an x value of 2 and a y value of 3 since it is in the fourth quadrant, the coordinates are (2, -3).

So the coordinates are {(–2, 1), (0, -1), (2, -3)} which is option d.

6 0
3 years ago
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