Carbon-12 has the following electron configuration: 1s2-2s2-2p2. As seen in the configuration, the right answer is: the first electron shell has 4 orbitals.
Answer:
See explanation below
Explanation:
The question is incomplete. However, here's the missing part of the question:
<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>
<em>C(s) + 2H2(g) <--> CH4(g). </em>
<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>
With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.
The expression of Kp for this reaction is:
Kp = PpCH4 / (PpH2)²
We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:
PpCH4 = Kp * PpH2²
*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.
Now solving for PpCH4:
PpCH4 = 0.455 * (1.78)²
<u><em>PpCH4 = 1.44 atm</em></u>
The relation between moles and mass is given by the formula:
# of moles = (mass in grams) / (molar mass)
So, given the molar mass of 18.02 and 0.025 mol, you can solve the formula for the mass of water in grams:
mass of water in grams = # of moles of water * molar mass of water
mass of water in grams = 0.025 mol * 18.02 g / mol = 0.4505 g of water.
Then, she is wrong.
The answer to your question would be A. hope this helps...
Answer:
You’re taking a walk on a warm fall morning. The temperature is about 70 degrees Fahrenheit, and you cannot see a cloud anywhere in the sky. You notice that the ground has no dew on it either. This means the <u>relative humidity</u> is low.