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N76 [4]
3 years ago
7

From your knowledge about the distribution of electrons in the levels and from the atomic number (in parentheses), indicate the

most likely charge on the ion when this atom forms an ion. (Remember the 2, 8, 18 level distribution.)
Answer Choices:
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+1
-2
+2
Chemistry
1 answer:
Simora [160]3 years ago
7 0
Hydrogen is a special case (there are a lot of special cases in chemistry)

Atomic number: 1

Electron configuration 1s1.

If hydrogen gains 1 electron it will form the ionn H- . This is feasible and likely to happen because with on additional electron the electron configuration will be 1s2, and it will complete the las shell (same confiugration of He) which is a stable confirguration.

Then the answer is 1-. But you will find that H can also loose its electron and form the ion H+.

A more representative analysis can be done with Oxygen, whose atomic number is 8 and the electron configuration is 2s2 2p6, then by gaining two electrons it will acquire the stable electron configuration of Ne: 2s2 2p8


By gaining two electrons, the ion has two negative charges, this is O 2-.

Whith this I have ilustrated the method: 1) use the atomic number to make the electron confirguration, 2) look at the valence electron shell and determine if it is easier to loose electrons or to gain electrons (gain 1 or two electrons is easier than loosing 7 or 6 electrons) to acquire the electron configuration of the closest Noble gas (full valence electron shell)
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Answer:

The answers to the question are

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(b) (O₂)

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Explanation:

(a) To solve the question we write the equation as follows

C + O₂ → CO₂

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The maximum mass of carbon dioxide that  can be formed = mass = moles × molar mass

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(b) The formula for  the limiting reagent (O₂)

Finding the limting reagent is by checking the mole balance of the reactants available to the moles specified in th stoichiometry of the reaction and selecting the reagent with the list number of moles

(c) The mass of excess reagent = 0.703 moles - 0.3009 moles = 0.4021 moles

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molar mass of mgnesium iodide = 278.1139 g/mol, number of moles of magnesium iodide in 23 g = 23g/ 278.1139 g/mol= 8.3 × 10⁻² M

Therefore the moles in 125 mL = (8.3 × 10⁻² M)/(125 mL) = (8.3 × 10⁻² M)/(0.125 L) = 0.662 M/L

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