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galina1969 [7]
3 years ago
13

What happens to sodium chloride when it dissolves in water

Chemistry
2 answers:
inn [45]3 years ago
7 0

Image result for What happens to sodium chloride when it dissolves in water

Explanation: On addition to water the Na+ section of NaCl is attracted to the oxygen side of the water molecules, while the Cl- side is attracted to the hydrogens' side of the water molecule. This causes the sodium chloride to split in water, and the NaCl dissolves into separate Na+ and Cl- atoms

Alisiya [41]3 years ago
6 0

Answer:

Sodium chloride will get dissociate in water on dissolving.

Explanation:

NaCl(aq)\rightarrow Na^+(aq)+Cl^-(aq)

Sodium chloride is an ionic compound which gets easily dissolve in water. When sodium chloride is dissolved in water is gets dissociated into sodium ions and chloride ions.

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Does the temperature of the solvent (water) affect the rate of dissolving?​
gregori [183]
Yes. Heating up the solvent gives the molecules more kinetic energy. The more rapid motion means that the solvent molecules collide with the solute with greater frequency and the collisions occur with more force. Both factors increase the rate at which the solute dissolves.
3 0
3 years ago
What is scientific "law"?
Natalka [10]
Based on (repeated) experiments or observations, that describe or predict a range of natural phenomena. the answer is c (sorry if i’m incorrect)
4 0
3 years ago
onsider the reaction, NO2(g) + CO(g) → NO(g) + CO2(g), for which the rate law has been determined to be: Rate = k[NO2]2[CO]. Whi
nlexa [21]

Answer:

The correct answer is option D.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

NO_2(g) + CO(g)\rightarrow NO(g) + CO_2(g)

Rate of the reaction:

R=-\frac{1}{1}\times \frac{d[NO_2]}{dt}=-\frac{1}{1}\times \frac{d[CO]}{dt}

Rate of decrease in nitrogen dioxide concentration is equal to the rate of decrease in carbon monoxide.

Given rate expression of the reaction:

R = k[NO2]^2[CO]

Rate of the reaction on doubling concentration of nitrogen dioxide and carbon monoxide : R'

R'=k(2\times [NO_2])^2(2\times [CO])=8\times k[NO2]^2[CO]=8R

Doubling the concentrations of nitrogen dioxide and carbon monoxide simultaneously will increase the rate of the reaction by a factor of eight.

Hence, none of the given statements are true.

6 0
3 years ago
Read 2 more answers
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
stich3 [128]

The given equation: Q + X ---> Products


4 0
3 years ago
How many kilograms of potassium iodide (ki) are needed to make 1.25 l of a 4.41 m ki solution?
Lapatulllka [165]
C = n/V
n = C×V
n = 4,41M × 1,25L
n = 5,5125 mol

mKI: 39+127 = 166 g/mol

1 mol --------- 166g
5,5125 mol --- X
X = 166×5,5125 = 915,075g KI

:)
7 0
3 years ago
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