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Sedaia [141]
3 years ago
14

A sample of polonium-210 has an initial mass of 390 milligrams (mg). If the half-life of polonium-210 is 36 days, how many mg of

the sample remains after 36 days?
A.
48.75 mg

B.
392 mg

C.
97.5 mg

D.
195 mg
Chemistry
1 answer:
Katarina [22]3 years ago
6 0

Answer:

d

Explanation:

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Calculate the number of grams of sodium in 2.00 g
Amiraneli [1.4K]

Answer:

A = 0.7871g

B = 0.8417g

C = 0.3192g

D = 0.3897g

Explanation:

Hello,

The number of grams of sodium (Na) in 2g of NaCl is

Molar mass of NaCl = 58.44g/mol

Molar mass of Na = 23g

23g of Na = 58.44g of NaCl

x g of Na = 2g of NaCl

x = (2 × 23) / 58.44

x = 0.7871g

Therefore, 0.7871g of Na is present in 2g of NaCl

2.

2g of Na₃PO₄

Molar mass of Na₃PO₄ = 163.94g/mol

Molar mass of Na = 23g

(3 × 23)g of Na = 163.94 g of Na₃PO₄

x g of Na = 2g of Na₃PO₄

x = (2 × 69) / 163.94

x = 0.8417g

0.8417g of Na is present in 2g of Na₃PO₄

3.

2g of NaC₇H₅O₂

Molar mass of NaC₇H₅O₂ = 144.103g/mol

Molar mass of Na = 23g

23g of Na = 144.103g of NaC₇H₅O₂

x g of Na = 2g of NaC₇H₅O₂

x = (2 × 23) / 144.103

x = 0.3192g

0.3192g of Na is present in 2g of NaC₇H₅O₂

4. 2g of Na₂C₆H₆O₇

Molar mass of Na₂C₆H₆O₇ = 236.08g/mol

Molar mass of Na = 23g

(2 × 23)g of Na = 236.08g of Na₂C₆H₆O₇

x g = 2g of Na₂C₆H₆O₇

x = (46 × 2) / 236.08

x = 0.3897g

0.3897g is present in 2g of Na₂C₆H₆O₇

5 0
3 years ago
What is the balanced NET ionic equation for the reaction when aqueous Cs₃PO₄ and aqueous AgNO₃ are mixed in solution to form sol
rusak2 [61]

Answer:

PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)

Explanation:

Hello!

In this case, since the net ionic equation of a chemical reaction shows up the ionic species that result from the simplification of the spectator ions, which are those at both reactants and products sides, we take into account that aqueous species ionize into ions whereas liquid, solid and gas species remain unionized. In such a way, for the reaction of cesium phosphate and silver nitrate we can write the complete molecular equation:

Cs_3PO_4(aq)+3AgNO_3(aq)\rightarrow Ag_3PO_4(s)+3CsNO_3(aq)

Whereas the three aqueous salts are ionized in order to write the following complete ionic equation:

3Cs^+(aq)+PO_4^{3-}(aq)+3Ag^+(aq)+3NO_3^-(aq)\rightarrow Ag_3PO_4(s)+3Cs^+(aq)+3NO_3^-(aq)

In such a way, since the cesium and nitrate ions are the spectator ions because of the aforementioned, the net ionic equation turns out:

PO_4^{3-}(aq)+3Ag^+(aq)\rightarrow Ag_3PO_4(s)

Best regards!

7 0
3 years ago
Two conditions are required for cloud formation:cooling of the air and
Lelechka [254]

Answer:

Presence of water molecules

Explanation:

Temperature decreases with an increase in altitude. At sufficiently high altitudes, the air is much colder than the air on the surface of the Earth. Water vapor has a low density and is capable to rise until it gets into a medium with a significantly low temperature and pressure to condense and produce water droplets out of water vapor. Those droplets then form clouds.

5 0
3 years ago
A gas has a volume of 590 ml at a temperature of -55.0°C. What volume will the gas occupy at 30.0°C?
Alexeev081 [22]

819 ml is the volume the gas will occupy at 30.0°C.

Explanation:

Data given:

initial volume of the gas V1 = 590 ml

initial temperature of the gas T1 = -55 degrees OR 218.15

final volume of the gas V2 = ?

final temperature of the gas T2 = 30 degrees OR 303.15

Charles' Law equation is used to calculate the volume of gas at 30 degrees from the data given in the question.

\frac{V1}{T1}= \frac{V2}{T2}

V2 = \frac{V1T2}{T1}

V2 = \frac{590 X 303.15}{218.15}

V2 = 819 ml

The final volume of the gas would be 819 ml.

6 0
4 years ago
What element is an atom that has 7 protons 8 neutrons and 6 electrons?
andreev551 [17]

Answer:

I think it should be Carbon.

6 0
3 years ago
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