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3 years ago

Write two different pairs of decimals whose sums are 8.69. one pair should involve regrouping.

Mathematics

2 answers:

Komok [63]3 years ago

6 0

No regrouping: 4.34 + 4.35
Regrouping (carrying): 4.93 + 3.76

Karolina [17]3 years ago

6 0

Answer:

The pairs are: No regrouping: 4.29+4.4 and Regrouping: 5.72+2.97

Step-by-step explanation:

Consider the provided information.

We need to write two different pairs of decimals whose sums are 8.69.

you can take any two number whose sum is 8.69

Let say first number is 4.29 then the second number will be 4.4

We can check this by adding the numbers as shown:

4.29

+4.4

8.69

It is required that one pair should involve regrouping.

You can take any two numbers whose sum is 8.69 after regrouping.

Let say first number is 5.72 then the second number will be 2.97

We can check this by adding the numbers as shown:

5.72

+2.97

8.69

Hence, the pairs are: No regrouping: 4.29+4.4 and Regrouping: 5.72+2.97

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There is a bag filled with 4 blue and 5 red marbles.

gavmur [86]

1) first pick red 5/9 blue 4/9

2) second pick when red has been picked red now becomes 4/8, blue stays 4/8

2) Second pick when blue has been picked blue now becomes 3/8, red stays 5/8

Mind you, you only need both different colours so:

first pick red 5/9 x sec pick blue 4/8 = 20/72

and first pick blue 4/9 x sec pick red 5/8 = 20/72

add both up 20/72 + 20/72 = 40/72 = 5/9

6 0

3 years ago

PLEASE HELP

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

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Sliva [168]

I think it’s what the other people said!

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Answer:

Step-by-step explanation:

I'm still not exactly sure what the question really is, but the level suggests that it is

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6*perpendicular slope = - 7

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