All categories

3 years ago

Help me find the volume of the prism please!!!!!!

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer:

1628.6cubic cm

Step-by-step explanation:

the volume of a cylinder formula:πr^2h

h(height)=3.6

π=3.14

r(radius)=12

3.14*12^2*3.6=

1628.6 cubic cm

hope this helps

koban [17]3 years ago

4 0

Answer:

$\large\boxed{V=518.4\pi\ cm^3\approx1,627.776\ cm^3}$

Step-by-step explanation:

The formula of a cylinder:

$V=\pi r^2H$

r - radius

H - height

We have r = 12cm and H = 3.6cm. Substitute:

$V=\pi(12^2)(3.6)=\pi(144)(3.6)=518.4\pi\ cm^3$

$\pi\approx3.14\\\\V\approx(518.4)(3.14)=1,627.776\ cm^3$

You might be interested in

What two consecutive integers does 20−−√ fall between?

Alex_Xolod [135]

Answer:

4 and 5

Step-by-step explanation:

8 0

3 years ago

A painter is painting a rectangular wall that measures 20.5 ft by 16.4 ft. Each gallon can of paint covers 200 square feet. What

alekssr [168]

The painter needs at least two gallons of paint to cover the wall.

To get this answer, you first need to find the area of the wall; by multiplying 20.5 x 16.4. This will get you 336.2.

Then, you need to divide 336.2 by 200. This will get you approx. 1.6.

If it's asking for partial gallons as well, stop here. Your answer is 1.6.

If not, continue.

Unless you're including partial gallons, you can't get 1.6 gallons of paint, so you need to round up. This will be 2 gallons.

5 0

2 years ago

Read 2 more answers

Please help! thanks :)

jeka94

Answer:

B- 583

Step-by-step explanation:

6% of 550 is 33. So, you just add 33 to 550 which equals 583.

Your welcome!

3 0

3 years ago

A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.022=0.0438$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = -0.058-0.0438=-0.102\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= -0.058+0.0438=-0.014$

The 95% confidence interval for the difference between proportions is (-0.102, -0.014).

7 0

3 years ago

How to factor 4(x+5)^3(x-1)^2-(x+5)^4 • 2 (x-1) by grouping?

nata0808 [166]

$\bf 4(x+5)^3(x-1)^2-(x+5)^4\cdot 2(x-1)
\\\\\\
4(x+5)^3(x-1)^2-2(x-1)(x+5)^4
\\\\\\ \underline{2}\cdot 2\underline{(x+5)^3}(x-1)\underline{(x-1)}~-~\underline{2}\underline{(x-1)}(x+5)\underline{(x+5)^3}\leftarrow 
\begin{array}{llll}
notice~the\\
common\\ \underline{factors}
\end{array}
\\\\\\
2(x+5)^3(x-1)~[~2(x-1)-(x+5)~]
\\\\\\
2(x+5)^3(x-1)~[2x-2-x-5]\implies 2(x+5)^3(x-1)(x-7)$

5 0

3 years ago