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3 years ago

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The distance between the manufacturing plant and Jessie’s home is 4 miles. It takes Jessie 40 minutes to walk that distance. Wri

te an equation with multiplication to find t, the time Jessie takes to cover one mile.

1 answer:

iVinArrow [24]3 years ago

3 0

Answer:

time taken to walk one mile × total distance in miles = total time

t × 4 = 40

Step-by-step explanation:

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The first derivative of x^2+2y^2=16 is -x/(2y), the second is -(2y^2+x^2)/(4y^3). Find the third implicit derivative of x^2+2y^2

gtnhenbr [62]

Answer:

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

Step-by-step explanation:

d²y/dx² = (-2y² − x²) / (4y³)

Take the derivative (use quotient rule and chain rule):

d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²

d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)

d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)

d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)

d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)

Substitute:

d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)

d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)

d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)

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3 years ago

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Musya8 [376]

Answer:

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Step-by-step explanation:

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2 years ago

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it costs $31.28 to fill your gas tank, which holds 16 gallons. find the price per gallon to fill your gas tank.

tia_tia [17]

Answer:

1.955

Step-by-step explanation:

$31.28 ÷ 16 = 1.955

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2 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

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3 years ago

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Clint is in study hall reading The hunger games. After 20 minutes, he is on page 151. After 45 minutes, he is on page 181. How m

alexdok [17]

Answer:

The number of pages had Clint read prior to study hall were <u>127 pages</u>.

Step-by-step explanation:

Given:

Clint after 20 minutes is on page 151.

And, after 45 minutes he is on page 181.

Now, to find the pages Clint read prior to study hall.

<em>The time difference = 45 minutes - 20 minutes.</em>

<em> = 25 minutes.</em>

<em>Difference between the pages = 181 - 151</em>

<em> = 30 pages.</em>

If Clint is reading each page at same speed.

Then, in 25 minutes he can read = 30 pages.

So, in 1 minute he can read = 30 ÷ 25 = 1.2 pages.

Thus, in 20 minutes he can read $=1.2\times 20$

$=24 pages.$

Now, number of pages Clint had read prior to study hall = 151 - 24

= 127 pages.

Therefore, the number of pages had Clint read prior to study hall were <u>127 pages</u>.

7 0

3 years ago