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zhannawk [14.2K]
2 years ago
12

1.-18(12) 2. -352 + -225

Mathematics
1 answer:
Montano1993 [528]2 years ago
8 0

Answer:

1.-204.5 2.-557

Step-by-step explanation:

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A conservative estimate of the number of stars in the universe is 6 x 10^22. The average human can see about 3,000 stars at nigh
Ilia_Sergeevich [38]

2 \times 10^{19} times more stars are there in universe compared to human eye can see

<h3><u>Solution:</u></h3>

Given that, conservative estimate of the number of stars in the universe is 6 \times 10^{22}

The average human can see about 3,000 stars at night with only their eyes

To find: Number of times more stars are there in the universe, compared to the stars a human can see

Let "x" be the number of times more stars are there in the universe, compared to the stars a human can see

Then from given statement,

\text{Stars in universe} = x \times \text{ number of stars human can see}

<em><u>Substituting given values we get,</u></em>

6 \times 10^{22} = x \times 3000\\\\x = \frac{6 \times 10^{22}}{3000}\\\\x = \frac{6 \times 10^{22}}{3 \times 10^3}\\\\x = 2 \times 10^{22-3}\\\\x = 2 \times 10^{19}

Thus 2 \times 10^{19} times more stars are there in universe compared to human eye can see

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3 years ago
Ebony bought 4 cans of Soup A for $6.00.
GREYUIT [131]
Soup b; no
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soup d; no
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3 years ago
help Kyle trying to explain to her friend why the placement of an ange and the concept of rigid motions can be used in determini
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Angle b = 31

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2 years ago
I don't know if this is right... please someone help mee
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For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

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this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
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3 years ago
How to show work for 36÷6
UkoKoshka [18]
36÷6 is 6 to show your work for it maybe draw it out and better show the equation like when you solve a bigger problem. 
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3 years ago
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