4.
h(f(x)=h(2x-1)=
(2x-1)^2+1=
4x²-4x+1+1=
4x²-4x+2
5.
f(f(x))=2(2x-1)-1=4x-2-1=4x-3
6.
f o g (x)=f(g(x))
h o g (x)=h(g(x))=
(3x)^2+1=
9x²+1
So in matt's equation, he made a mistake in the a transision from line 2 to line 3
in line 2: -4(-2)2
in line 3: -4(4)
the mistake is that -2 times 2 is not equal +4 it is equal to -4
also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5
so he first subtracted 10 then divided, he should have divided then subtracted
so the equation should have equaled
Karen used the correct (-) times (+) property and the order of operations
so Karen is correct and Matt is wrong.
Answer:
w(2w+4)
Step-by-step explanation:
we know A = l * w
and Perimeter = 2l + 2w
we want to find l in terms of w
2l + 2w = 6w + 8
2l = 4w + 8
l = 2w + 4
so A = w * (2w + 4)