Antibiotics should be the answer
Answer:
The correct answer is -
A) BbTt x bbTt
B) .5^4 or 1/16 or 0.0625
Explanation:
As it is given that Brachydactylus and PTC tasters both traits are autosomal dominant conditions which mean only one allele would be enough.
For Branchydactylus and For tasting : man and women will be heterogeneous.
Hence,
The Genotype of man = BbTt
The Genotype of wife = bbTt
b. Answer = 0.0625
For Branchydactylus:
Bb X bb
Possible genotypes:
B b
b Bb( Brachydactylus) bb(normal)
b Bb (Brachydactylus) bb (normal)
The probability of a single child being Branchydactylus = 2/4 = 0.5
So, Probability of all 4 child being Branchydactylus = .5 x .5 x .5 x .5 = 0.0625
Answer:
mutualistic
Explanation:
The interaction between two organisms in which both the organism gets benefitted from each other is called a mutualistic relationship. This mutualistic relationship is seen in the concept of endosymbiosis.
According to the endosymbiotic theory chloroplast and mitochondria are evolved by engulfment of different bacteria by ancestral cells. Then these bacterial remained in a mutualistic relationship with each other and the ancestral cell evolved into a eukaryotic cell.
So as mitochondria and chloroplast live with a symbiotic relationship with eukaryotic cells, therefore, it is considered as mutualistic relationship.
The terminal cisternae releases calcium ion
The terminal cisternae act as calcium storage sites. The calcium ions stored in the terminal cisternae are essential in muscle contraction. The calcium release unit of muscle consists of terminal cisternae of the sarcoplasmic reticulum and it is adjacent transverse or T- tubule that is the invaginated part of the surface membrane.