The function of the object height is an illustration of a projectile motion
The object will never hit the ground
<h3>How to determine when the object hits the ground?</h3>
The function is given as:
h=16t^2+80t+96.
When the object hits the ground, h = 0
So, we have:
16t^2+80t+96 = 0
Divide through by 16
t^2+5t+6 = 0
Expand
t^2 + 3t + 2t + 6 = 0
Factorize
t(t + 3) + 2(t + 3) = 0
Factor out t + 3
(t + 2)(t + 3) = 0
Solve for t
t = -2 or t = -3
The time (t) cannot be negative.
Hence, the object will never hit the ground
Read more about projectile motion at:
brainly.com/question/1130127
86/139*100%= 61.87%
The final answer is 61.87%~
Answer:
12
Step-by-step explanation:
2/3 x + x = 20
2/3 x + 3/3x = 20
5/3 x = 20 ... times 3/5 both sides
x = 12
check: 2/3 x 12 + 12 = 8 + 12 = 20
y = -5x + 24
y = 4x - 21
Since both of these equations are equal to Y, theyre equal to each other.
So we can make an equation with y = -5x + 24 in one side and y = 4x - 21 on the other.
-5x + 24 = 4x - 21
Now in order to get the value of x we need to isolate it in one side of the equation. We can do this by subtracting 24 from both sides of the equation:
-5x + 24 - 24 = 4x - 21 - 24
-5x = 4x - 45
Now we subtract 4x from both sides so the 4x shift to the other side
-5x - 4x = 4x - 4x - 45
-9x = -45
Finally divide both sides by -9 so x is by itself
(-9)÷(-9x) = -(45)÷(-9)
x = 5
Since we did all of this to BOTH sides of the equation, both sides are still equal to each other and the equation still is true.
Now apply x = 5 to either of the initial equations to find the value of Y
y = -5x + 24 or y = 4x - 21
(I'll do both but u only need one)
y = -5(5) + 24
y = -25 + 24
y = -1
y = 4(5) - 21
y = 20 - 21
y = -1
Either way, X is 5 and Y is -1
Answer (5, -1)
