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Anvisha [2.4K]
3 years ago
11

You are working at a clothing store where your weekly

Mathematics
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

n=900

Step-by-step explanation:

the equation is:

197=125+0.08n

72=0.08n

n=900

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Simplify <br> −5x^4(−3x^2+4x−2)
malfutka [58]
112 me dió a eso mira haber si es si no trate.
6 0
3 years ago
an object of mass 300kg is observed to accelerate at the rate of 4 m/s^2. Caculate the force required to produce this accelerati
icang [17]

Answer:

1200 N

Step-by-step explanation:

Newton's second law:

F = ma

F = (300 kg) (4 m/s²)

F = 1200 N

4 0
3 years ago
PLS ANSWER WHAT IS 3 and 14 hundredths minus 1 and 9 hundredths?
k0ka [10]

Answer:

2 and 5 hundredths

Step-by-step explanation:

3 - 1 = 2

14 hundredths - 9 hundredths = 5 hundredths

hence you get 2 and 5 hundredths

6 0
3 years ago
Mark and Zoe are hiking a trail. Mark starts before Zoe. The expression 2t + 100 represents how far, in meters, Mark has hiked t
olasank [31]

Answer: No

Step-by-step explanation:

The distance hiked of Mark is represented by 2*t + 100

and the distance hiked of Zoe is represented by 2*t

here, you can see that the slope of both equations is equal, this means that in the same lapse of time, Zoe and Mark displace the same amount, but because Mark started earlier, he has a y-intercept bigger than zero, so for every value of t, the distance that Mark hiked will be higher than the one of Zoe.

We can represent this by:

2*t + 100 > 2*t

100 > 0

So the distance hiked by Mark is always bigger than the one of Zoe

7 0
3 years ago
Read 2 more answers
Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)
lozanna [386]
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Distance = \sqrt{(-3-3)^2+(5-2)^2}

Distance = \sqrt{(-6)^2+3^2}

Distance = \sqrt{36+9}

Distance = \sqrt{45}\approx6.7082

6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}
8 0
3 years ago
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