Answer:
1.33 moles CO2
Explanation:
The number you are converting is 58.4 g CO2, so you start with this value. The conversion factor is 44.0 g/mol CO2. In order to cross out the grams, the grams must go on the bottom of the conversion factor.
1 mol CO2
58.4 g CO2 x -------------------------- = 1.33 moles CO2
44.0 grams
The answer has three sig figs.
Answer :
The parent and daughter concentrations (in percentages) is, 60 % and 40 % respectively.
The age of rock is 
Explanation :
First we have to calculate the parent and daughter concentrations (in percentages).
and,
As we know that, the half-life of uranium-238 = 
years
Now we have to calculate the rate constant, we use the formula :
Now we have to calculate the time passed.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = 
t = time passed by the sample = ?
a = initial amount of the reactant = 3 g
a - x = amount left after decay process = 1.8 g
Now put all the given values in above equation, we get
Therefore, the age of rock is
Answer:
The wave with the wavelength of 8.82 nm have frequency of 0.340 × 10¹⁷ s⁻¹.
Explanation:
Given data:
Wavelength of x-ray = 8.82 nm
frequency of x-ray = ?
Solution:
speed = Wavelength × frequency
frequency = speed / Wavelength
c = 3 × 10⁸ m/s
f = c/ λ
f = 3 × 10⁸ m/s /8.82 × 10⁻⁹m
f = 0.340 × 10¹⁷ s⁻¹
The wave with the wavelength of 8.82 nm have frequency of 0.340 × 10¹⁷ s⁻¹.
The number of mole of S₂O₃ produced from the reaction is 13.33 moles
<h3>Balanced equation </h3>
4Sb + 3O₂ —> 2S₂O₃
From the balanced equation above,
3 moles of O₂ reacted to produce 2 moles of S₂O₃
<h3>How to determine the mole of S₂O₃ produced </h3>
From the balanced equation above,
3 moles of O₂ reacted to produce 2 moles of S₂O₃.
Therefore,
20 moles of O₂ will react to to produce = (20 × 2) / 3 = 13.33 moles of S₂O₃.
Thus, 13.33 moles of S₂O₃ were obtained from the reaction.
Learn more about stoichiometry:
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