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makvit [3.9K]
3 years ago
9

Which compound is used to make asphalt?

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
6 0
Asphalt<span>/bitumen is </span>used to make<span> Japan black, a lacquer known especially for its use on iron and steel,</span>
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A student determines that 23.1 J of heat are required to raise the temperature of 6.67 g of an
Semenov [28]

A student determines that 23.1 J of heat are required to raise the temperature of 6.67 g of an

5 0
2 years ago
Bilangan oksidasi vanadium paling tinggi terdapat dalam senyawa..
emmasim [6.3K]
The answer is (b). As, vanadium is attached to five fluoride atoms, each flouride containing -1 oxidation state, hence five fluoride contains -5, to neutralize, vanadium should have +5 oxidation state.

8 0
3 years ago
A 35.66g sample of copper is heated using 600j of energy. if the original temperature of the copper is 85C what is its final tem
ira [324]

This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.

Thus, we recall the general heat equation:

Q=mC(T_f-T_i)\\

Which has to be solved for the final temperature, T_f as follows:

T_f=T_i+\frac{Q}{mC}

Finally, we plug in the numbers to obtain:

T_f=85\°C+\frac{600J}{35.66g*0.38\frac{J}{g\°C} } \\\\T_f=129.3\°C

However, this result is not given in the choices.

Learn more:

  • brainly.com/question/14383794
8 0
2 years ago
Find the fugacity coefficient of a gaseous species of mole fraction 0.4 and fugacity 25 psia in a mixture at a total pressure of
Oksana_A [137]

<u>Answer:</u> The fugacity coefficient of a gaseous species is 1.25

<u>Explanation:</u>

Fugacity coefficient is defined as the ratio of fugacity and the partial pressure of the gas. It is expressed as \bar{\phi}

Mathematically,

\bar{\phi}_i=\frac{\bar{f_i}}{p_i}

Partial pressure of the gas is expressed as:

p_i=\chi_iP

Putting this expression is above equation, we get:

\bar{\phi}_i=\frac{\bar{f_i}}{\chi_iP}

where,

\bar{\phi}_i = fugacity coefficient of the gas

\bar{f_i} = fugacity of the gas = 25 psia

\chi_i = mole fraction of the gas = 0.4

P = total pressure = 50 psia

Putting values in above equation, we get:

\bar{\phi}_i=\frac{25}{0.4\times 50}\\\\\bar{\phi}_i=1.25

Hence, the fugacity coefficient of a gaseous species is 1.25

8 0
2 years ago
The addition of 0.275 L of 1.62 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions
musickatia [10]

Answer:

The mass of PbCl₂ is 45.88 grams and the mass of AgCl is 16.48 grams.

Explanation:

As mentioned in the given question, the addition of 0.275 L of 1.62 M KCl is done in a solution that comprise Ag⁺ and Pb²⁺ ions so that all the ions get precipitated. Therefore, the moles of KCl present is,  

Moles of KCl = 0.275 L × 1.62 M = 0.445 moles

Now the reaction will be,  

Ag⁺ + Pb²⁺ + KCl ⇒ AgCl + PbCl₂ + 3K⁺

Now let us assume that the formation of x moles of AgCl and y moles of PbCl₂ is taking place.  

Therefore, mass of AgCl will be x × molecular mass, which will be equal to x × 143.32 grams = 143.32 x grams

Now the mass of PbCl2 formed will be,  

y × molecular mass = y × 278.1 grams = 278.1 y grams

Now the total precipitate will be,  

62.37 grams = 143.32 x + 278.1 y -----------(i)

Now as AgCl and PbCl₂ requires 1:2 ratio of KCl, this shows that x moles of AgCl will require x moles of KCl and y mol of PbCl₂ will require 2*y moles of PbCl₂. Therefore,  

x + 2y = total mass of KCl

x + 2y = 0.445 moles ------ (ii)

On solving equation (i) and (ii) we get,  

x as 0.115 and y as 0.165

Now the mass of AgCl will be,  

143.32 × 0.115 = 16.48 grams

The mass of PbCl₂ will be,  

278.1 × 0.165 = 45.88 grams.  

3 0
3 years ago
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