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77julia77 [94]
3 years ago
10

Solve system of equations by substitution

Mathematics
1 answer:
loris [4]3 years ago
5 0
(1,3) 

You plug the equation that equals y into the y value on the other equation that equals 4. Then, you plug the x value into the x on the equation that equals y. Sorry if that was confusing
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Free_Kalibri [48]
The area of 4 and 9 is 36 because you multiply the width and length
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Write the standard form of a line that passes through (1, 1) and (3, 4)
Sophie [7]

Answer:

3x - 2y = 1

Step-by-step explanation:

Step 1:   Find the slope

slope m = (y2 - y1)(/x2 - x1)

 m = (4 - 1)/(3 - 1) = 3/2

Step 1:  Use the formula y = mx + b to solve

This is slope-intercept form of a line.  We have a slope of 3/2, and a point (x, y), which is (1, 1).  Plug those values into the equation above and solve for b (the only variable we are missing

1 = (3/2)(1) + b

   1 = 3/2 + b  

          1 - 3/2 = b

             2/2 - 3/2 = b

                  -1/2 = b

Step 2: Rewrite the formula using the slope and the b value we just calculated

 y = (3/2)x - 1/2

Step 3:  Standard form of a line is ax + by = c, where a is a positive integer, so we rearrange the equation from step 2 to standard form.  

y = (3/2)x - 1/2

 -(3/2)x + y = -1/2     (subtract (3/2)x from both sides)

 

      -3x + 2y = -1       (multiply by 2 to get rid of the fraction on x)

           3x - 2y = 1     (multiply by -1 so a becomes positive)    

3 0
3 years ago
6<br> in.<br> 2 in.<br> find area
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Answer:

12in squared

Step-by-step explanation:

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Bess [88]

Answer:

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Explanation:

Use this system of equations if G=George and J=Jeannie:

G-12=J

50=(G+5)+(J+5)

So, change second equation becomes

40-G=J

Then use substitution:

G-12=40-G

2G=52

G=26

Then, to find Jeannie’s age, go back to one of the equations and substitute G.

26-12=J

So, J=14

Jeannie is currently 14 years old.

4 0
3 years ago
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Answer po plss plssplsss
erica [24]

Answer:

I'll answer 6 to 10 cuz that's only what I'm able to see

Step-by-step explanation:

6.

Y-Z

= {6,4,7,2,8,3} - {2,7,8,9,10}

= {6,4,3}

7.

( Y ∪ Z ) ∩ X

= ( {6,4,7,2,8,3} ∪ {2,7,8,9,10} ) ∩ {1, 2,3,5,8}

= { 2,3,4,6,7,8,9,10} ∩ {1, 2,3,5,8}

= {2,3,5,8}

8.

( X ∪ Y ) ∩  ( Y ∪ Z )

= ( {1, 2,3,5,8} ∪ {6,4,7,2,8,3} ) ∩ ( {6,4,7,2,8,3} ∪ {2,7,8,9,10} )

= {1,2,3,4,5,6,7,8} ∩ {2,3,4,6,7,8,9,10}

= {2,3,4,6,7,8}

9.

( X ∩ Z ) ∪ ( X ∩ Y )

= ( {1,2,3,5,8} ∩ {2,7,8,9,10} ) ∪ ( {1,2,3,5,8} ∩ {6,4,7,2,8,3} )

= {2,8} ∪ {3,8}

= {2,3,8}

10.

( X ∪ Y ) ∩ Z

= ( {1,2,3,5,8} ∪ {6,4,7,2,8,3} ) ∩ {2,7,8,9,10}

= {1,2,3,4,5,6,7,8} ∩ {2,7,8,9,10}

= {2,7,8}

7 0
3 years ago
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