Answer:
number 1 the outliers....................
First setup the system of equations for the given case.
Let sandwich=x
and delivery fee =y
Equations are:
4x+y=33 Equation 1
8x+y=61 Equation 2
Subtract equation 1 from 2.
4x=28
x=7
Now substitute value of x in equation 1.
4(7)+y=33
28+y=33
y=5
So cost of single sandwich=$7 and Delivery fee=$5
Now cost of 12 sandwiches:
12x+y=85
Put y=5
12x+5=85
12x=80
x=6.67 which is less than 7. So, They are not able to get 12 sandwiches for $85.
Answer:
Step-by-step explanation:
Ignore the A before the ±. It wouldn't let me type it correctly.
x² + 2x - 5 = 0
a = 1
b = 2
c = - 5
Two separate equations
Answer:
4.5
Step-by-step explanation:
Answer:
x = - 9, x = 0, x = 7
Step-by-step explanation:
Given
x(x - 7)(x + 9) = 0 ← in standard form
Equate each factor to zero and solve for x
x = 0 ⇒ x = 0
x - 7 = 0 ⇒ x = 7
x + 9 = 0 ⇒ x = - 9
