Question

Write an equation of the line that passes through (4,−1) and is parallel to the line y=3x+7.

Answer 1

Answer:

$y = 3x - 13$

Step-by-step explanation:

The equation of parallel line differ only by their constant.

Hence, the equation of the line parallel to $y = 3x + 7$ is nothing but $y = 3x + c$.

When a point passing through this line is given we can substitute the point in this line and get the value for $c$.

The line passes through $(4, -1)$.

Therefore, we have: $-1 = 3(4) + c$

$\implies c = -13$.

Substituting this we get the equation of the parallel line as $y = 3x - 13$.