Answer:
units.
Step-by-step explanation:
The given functions are:
and
The function has y-intercept , .
The function has y-intercept,
If we shift the graph of g(x) up to obtain f(x), then the y-intercept must move from to .
This means that the graph will move up by;
units.
This is a quadrilateral, so the sum of interior angle measures, like a rectangle or square ( who’s interior angle measures are4 x 90) —— is 360
So ...
E + 89 + 130 + 90 = 360
E + 309 = 360
- 309 - 309
E = 51 degrees
Answer:
-6 on a number line is closer to 0 which make sit greater while -9 is farther away which makes it less than -6
Step-by-step explanation:
Answer:
a. 8 outcomes
b. Discrete Variable
c. See explanation below
Step-by-step explanation:
a.
Let N = No Offers made
Let Y = Offers made
The Expected outcome are as follows:
NNN, NNY, NYN, YNN, NYY, YNY, YYN, YYY
= 8
b.
Let x = number of offers made
X is said to be discrete if x can take values that are restricted to a defined or limited values
X is said to be continuous if x can take a range of values that is not restricted to any range(i.e. continuous)
Looking at the brief description above, we can conclude that x is discrete
c.
NNN, 0
NNY, 1
NYN, 1
YNN, 1
NYY, 2
YNY, 2
YYN, 2
YYY, 3
Where 0 to 3 represents number of offers at every instance
<h3>
Answer: False</h3>
==============================================
Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
--------------------------
Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.