Answer:
One way to factor equation is to find the zeros. Its obvious that x=-1 is solution for this. So one factor is (x+1)
the next factor should include 2x at first (because we have 2x^2 in the equation which can not be made any other way)
Let's suppose the factor is (x+1)(2x+b)
Since we do not know what is b open the brackets 2x^2+bx+2x+b. If this is equal to 2x^2+5x+3 then b=3. We are left with (x+1)(2x+3)=2(x+1)(x+3/2)
Would go for other shorter solutions, but they require some deeper understanding like Horner's scheme,Fermat's Theorem or even deeper which I assume You will not understand)
Answer:
6,10,14,18,22
Step-by-step explanation:
4n+2
Let n=1 4(1)+2 = 4+2 = 6
Let n=2 4(2)+2 = 8+2 = 10
Let n=3 4(3)+2 = 12+2 = 14
Let n=4 4(4)+2 = 16+2 = 18
Let n=5 4(5)+2 = 20+2 = 22
Answer:
Not clear of the question
Step-by-step explanation:
Yeshgggghhgfgggggggy. B be cc
The missing values represented by x and y are 8 and 20, that is
(x, y) = (8, 20)
The function y = 16 + 0.5x is a linear equation that can be solved graphically. This means the values of both variables x and y can be found on different points along the straight-line graph.
The ordered pairs simply mean for every value of x, there is a corresponding value of y.
The 2-column table has values for x and y which all satisfy the equation y = 16 + 0.5x. Taking the first row, for example, the pair is given as (-4, 14).
This means when x equals negative 4, y equals 14.
Where y = 16 + 0.5x
y = 16 + 0.5(-4)
y = 16 + (-2)
y = 16 - 2
y = 14
Therefore the first pair, just like the other four pairs all satisfy the equation.
Hence, looking at the options given, we can determine which satisfies the equation
(option 1) When x = 0
y = 16 + 0.5(0)
y = 16 + 0
y = 16
(0, 16)
(option 2) When x = 5
y = 16 + 0.5(5)
y = 16 + 2.5
y = 18.5
(5, 18.5)
(option 3) When x = 8
y = 16 + 0.5(8)
y = 16 + 4
y = 20
(8, 20)
From our calculations, the third option (8, 20) is the correct ordered pair that would fill in the missing values x and y.
To learn more about the straight line visit:
brainly.com/question/1852598
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