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Llana [10]
3 years ago
15

BCD∼EFGH

Mathematics
2 answers:
Rashid [163]3 years ago
7 0
For whatever reason, Brainly questions are often missing the first character. Here, we assume it is A, so that the intended statement is ABCD~EFGH.

FG = BC*(EH)/AD = 15*60/45 = 20 . . . . inches
Schach [20]3 years ago
4 0

Answer:

Step-by-step explanation:

Alright, lets get started.

ABCD and EFGH are given as similar.

Hence their ratios of the sides will be same.

It means:

\frac{AD}{EH}=\frac{BC}{FG}

Putting the values

\frac{45}{60}=\frac{15}{x}

Cross multiplying

45x = 60*15

Dividing 45 in both sides

x=20

Hence the side FG = 20 in    :    Answer

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Given JKMN is a square and NM= 4x and KM = 6x - 16, find all missing angle measures and side lengths.
kirza4 [7]

Answer:

The side lengths are 32 units each

Step-by-step explanation:

Given

NM= 4x

KM = 6x - 16

Required

The side lengths and missing angles

Since JKMN is as square, then:

NM = KM -- all sides are equal

4x = 6x - 16

Collect like terms

4x - 6x = - 16

-2 x = - 16

Divide by -2

x = 8

Substitute x = 8 in NM= 4x

NM = 4 * 8

NM = 32

The missing angles can't be solved without an attachment.

<em>However, if the missing angles are the angles at the edges of the square, then they measure 90 degrees each (i.e. angles at right angle)</em>

3 0
3 years ago
These Questions are confused me a lot help if you could I really appreciate it thank you
matrenka [14]
<h3><em><u>Answers With Steps:</u></em></h3><h3>Question 1:</h3>

For the first problem, understand that you are solving for the area of a circle. The equation for the area of a circle is pi r². By using the leash length as the radius (r), you can get the answer. (The leash length is 3 meters long.)

<em>Question 1 Steps:</em>

pi 3² --->  pi * 9 ---> ≈28.27

<em>Question 1 Answer:</em>

It would have about 28.27 meters² of playable space.

<h3>Question 2:</h3>

For the second problem, it would be much the same as to the first question. There is the same objective to find the area of the circle. Along with that, it gives us a length to work with. This time it is the sprinkler's reach, which would be the radius, or "r" in the equation.

<em>Question 2 Steps:</em>

pi 5² ---> pi * 25 ---> ≈78.54

<em>Question 2 Answer:</em>

The sprinkler would have about 78.54 feet² of space that it can reach.

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