Answer:
The total distance will be 400 m.
Explanation:
For portion AB:
Acceleration = 2
t= 10 s
Car start from rest , u=0 m/s
We know that


S= 100 m.
For portion BC:
V= u + at
V=0 + 2 x 10
V= 20 m/s
In this portion car moves with constant velocity 20 m/s for 10 s.
So distance S= V x t
S=20 x 10 =200 m.
For portion CD:
The velocity at point C will be 20 m/s
In this portion the final speed of car will be zero because given that at final car come to rest.
So the acceleration will be in the negative direction to stop the car.
We know that


S=100 m
The total distance AD=AB + BC+ CD
AD=100 +200 + 100 m
AD=400 m.
The total distance will be 400 m.
Answer:
0.38°
Explanation:
= Angle
m = Number
d = Distance
n = Refractive index of liquid = 1.25
a denotes air
l denotes liquid
In the case of double split interferance we have the relation

For air

For liquid

Dividing the two equations

Wavelength ratio = 

The angular separation is 0.38°
momm=massxvelocity
momm=1200x2.5=120x25=600x5=3000kgm/s
To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.

If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,



So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb
Answer:
D,B,C,A,C
Explanation:
I believe that is the correct answers but it is unclear. I don't think the key for the second last question would let the current flowing so the bulb would be off.