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skad [1K]
3 years ago
9

A student makes a simple pendulum by attaching a mass to the free end of a l.50-meter length of string suspended from the ceilin

g of her physics classroom. She pulls the mass up to her chin and releases it from rest, allowing the pendulum to swing in its curved path. Her classmates are surprised that the mass doesn't reach her chin on the return swing, even though she does not move. Why does the mass not have enough energy to return to its starting position and hit the girl on the chin?
Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

The answer to the question are

  • Air resistance
  • Friction
  • Kinetic energy converted to other forms of energy for example internal energy.

Explanation:

This is due to the change of a portion of the kinetic energy of the swinging pendulum to other forms of energy to overcome the resistance to its motion . This is known as losses of energy

The energy losses  of the incurred by the swinging pendulum include

1. Drag from air resistance - This creates turbulence in the in the air surrounding the moving pendulum

2. Frictional resistance from the pendulum attachments -  this creates heat and sound at the point of attachment of the string

3. Conversion of kinetic energy to other forms of internal energy.

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A car starting from rest accelerates at a constant 2.0 m/s2 for 10 s. It then travels with constant speed it has achieved for an
Anon25 [30]

Answer:

The total distance will be 400 m.

Explanation:

For portion AB:

Acceleration = 2m/s^2

t= 10 s

Car start from rest , u=0 m/s

We know that

S=ut+\dfrac{1}{2}at^2

S=0+\dfrac{1}{2}\times 2\times 10^2

S= 100 m.

For portion BC:

V= u + at

V=0 + 2 x 10

V= 20 m/s

In this portion car moves with constant velocity  20 m/s for 10 s.

So distance S= V x t

S=20 x 10 =200 m.

For portion CD:

The velocity at point C will be 20 m/s

In this portion the final speed of car will be zero because given that at final car come to rest.

So the acceleration will be in the negative direction to stop the car.

We know that

v^2=u^2-2aS

0=20^2-2\times 2\times S

S=100 m

The total distance AD=AB + BC+ CD

AD=100 +200 + 100 m

AD=400 m.

The total distance will be 400 m.

4 0
3 years ago
A double-slit arrangement produces interference fringes for sodium light (λ = 589 nm) that are 0.48° apart. What is the angular
larisa [96]

Answer:

0.38°

Explanation:

\theta = Angle

m = Number

d = Distance

n = Refractive index of liquid = 1.25

a denotes air

l denotes liquid

In the case of double split interferance we have the relation

m\lambda=dsin\theta

For air

m\lambda_a=dsin\theta_a

For liquid

m\lambda_l=dsin\theta_l

Dividing the two equations

\frac{m\lambda_a}{m\lambda_l}=\frac{dsin\theta_a}{dsin\theta_l}\\\Rightarrow \frac{\lambda_a}{\lambda_l}=\frac{sin\theta_a}{sin\theta_l}

Wavelength ratio = n

n=\frac{sin\theta_a}{sin\theta_l}\\\Rightarrow \frac{sin0.48}{1.25}=sin\theta_l\\\Rightarrow \theta_l=sin^{-1}\frac{sin0.48}{1.25}\\\Rightarrow \theta_l=0.38^{\circ}

The angular separation is 0.38°

5 0
4 years ago
Read 2 more answers
3. Calculate the momentum of a 1200kg car with a velocity of 25m/s.
antiseptic1488 [7]

momm=massxvelocity

momm=1200x2.5=120x25=600x5=3000kgm/s

4 0
4 years ago
A crowbar 2727 in. long is pivoted 66 in. from the end. What force must be applied at the long end in order to lift a 600600 lb
NikAS [45]

To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.

\sum \tau = F*d

If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,

F*(27-6)= 6*600

F = \frac{6*600}{21}

F= 171.42 lb

So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb

4 0
3 years ago
Can anyone plz help me ​
juin [17]

Answer:

D,B,C,A,C

Explanation:

I believe that is the correct answers but it is unclear. I don't think the key for the second last question would let the current flowing so the bulb would be off.

8 0
3 years ago
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