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skad [1K]
3 years ago
9

A student makes a simple pendulum by attaching a mass to the free end of a l.50-meter length of string suspended from the ceilin

g of her physics classroom. She pulls the mass up to her chin and releases it from rest, allowing the pendulum to swing in its curved path. Her classmates are surprised that the mass doesn't reach her chin on the return swing, even though she does not move. Why does the mass not have enough energy to return to its starting position and hit the girl on the chin?
Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

The answer to the question are

  • Air resistance
  • Friction
  • Kinetic energy converted to other forms of energy for example internal energy.

Explanation:

This is due to the change of a portion of the kinetic energy of the swinging pendulum to other forms of energy to overcome the resistance to its motion . This is known as losses of energy

The energy losses  of the incurred by the swinging pendulum include

1. Drag from air resistance - This creates turbulence in the in the air surrounding the moving pendulum

2. Frictional resistance from the pendulum attachments -  this creates heat and sound at the point of attachment of the string

3. Conversion of kinetic energy to other forms of internal energy.

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What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
emmainna [20.7K]

Answer:

14,300 lines per cm

Explanation:

Given that

The wavelength of visible light ranges from 400 nm to 400nm

It is possible to find the maximum number of lines per cm. This maximum number of lines per cm is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ), where

m = order of diffraction.

λ = wavelength of the incident light.

d = distance between the centers of the two slits.

θ = angle of diffraction of the mth order.

In order to find the least separation that allows the observation of one complete order of spectrum of the visible region, we make use the maximum or highest wavelength of the visible region that we are given, which is 700 nm.

d = mλ / sin (θ)

Again, we need the distance d to be the smallest, so sin (θ) must be the greatest, and for sin (θ) to be the greatest, it has to be equal to 1. Using the longest wavelength is the best idea because when the smallest wavelength is used the longest wavelength would not be diffracted.

d = mλ / sin (θ)

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3 0
3 years ago
Hi please answer and show your work​
jek_recluse [69]

Answer:

\huge\boxed{\sf P.E. = 240\ MJ}

\huge\boxed{\sf K.E. = 19.6\ MJ}

Explanation:

<u>Given:</u>

Mass = m = 200,000 kg

Vertical Distance = h = 120 m

Speed = v = 14 m/s

Acceleration due to gravity = g = 10 m/s²

<u>Required:</u>

1) Gravitational Potential Energy = P.E = ?

2) Kinetic Energy = K.E. = ?

<u>Formula:</u>

1) P.E. = mgh

2) K.E. = \displaystyle \frac{1}{2} mv^2

<u>Solution:</u>

1) P.E. = (200,000)(10)(120)

P.E. = 240,000,000 Joules

P.E. = 240 Mega Joules

P.E. = 240 MJ

2) K.E. = 1/2 (200000)(14)^2

K.E. = (100000)(196)

K.E. = 19,600,000 Joules

K.E. = 19.6 MJ

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
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