Answer:
$6.68
Explanation:
The current running through the device would be its outlet voltage divided by the resistance:
I = U/R = 115 / 11.4 = 10.09 A
The power generated by this device is the product of its current and voltage
P = IU = 10.09 * 115 = 1160 W or 1.16 kW
If running this device for 36 hours then the total energy it would consume is
E = Pt = 1.16 * 36 = 41.76 kWh
Therefore the total cost of electrical energy is
C = Ec = 41.76*0.16 = $6.68
Coprolites is actually fossilized poop, so...by examining that, scientists can see what the dinosaur ate.
Answer:
The correct answer to the question is
Both A and B are true
Explanation:
The particles of a gas are free to move to occupy the entire volume in which they are placed due to the smallerinter molecular forces holding them together hence due to the face that pressure is a measure of the Force per unit area that is Pressure P = ( Force F)/ (Area A) then the force per unit area, exerted on the all of the container by the gaseous particles which are colliding with each other and with the walss of the container is fairly constant through out the surface oof the container
In the case of the liquid which are held on together by more stronger forces, the force per nit area exerted by the liquid particle is transmitted from one particle to the next until it reaches the container's surface. Then remembering that the force of gravity on the liquid is acting in one direction (that is downwards) the sum of the fprce due to the weight incrreases as we progress deaper into the liquid hence the pressure increases per unit depth
The period of the planet is 58.1 years
Explanation:
We can solve this problem by using Kepler's third law, which states that:
"The square of the orbital period of a planet is proportional to the cube of its semimajor orbital axis"
Translated into equations, we can write:
Where, taking the orbits of the planets as almost circular, we have:
is the orbital period of the unknown planet
is the radius of the orbit of the planet
(1 year) is the period of the orbit of the Earth
is the orbital radius of the Earth
Solving for , we find the orbital period of the unknown planet:
Learn more about Kepler's third law:
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