Electrons that are the highest energy level is called Valence Electrons
it all depends on Region and how long they have been there some minerals crush faster then some others so some might only take a few thousand while others might take millions
Answer:
Explanation:
A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km
Check attachment for diagram
The intensity of the position vector is equal to the displacement,
So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.
So, applying Pythagorean theorem
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
Verifique el adjunto para ver el diagrama
La intensidad del vector de posición es igual al desplazamiento,
Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.
Entonces, aplicando el teorema de Pitágoras
c² = a² + b²
R² = 6² + 36²
R² = 36 + 64
R² = 100
R = √100
R = 10 km.
Answer:
Answer A : Fusion followed by beta decay (electron emission)
Explanation:
Notice that you want the Atomic number to increase, that is the number of protons in a nucleus. So if all four cases given experience the same fusion of nuclei, the only one that net increases the number of protons in the last stage, is the reaction that undergoes a beta decay (with emission of an electron) thus leaving a positive imbalance of positive charge (proton generated in the beta decay of a neutron).
Therefore, answer A is the correct one.
Explanation:
It is given that the value of P is 1110 N. And, for pin connection we have only two connections which are
and
. Let T be the tension is rope.
So,
and
- 1110 = 0

= 0
And,
= 0
T = 
Also,
= 0
1110(0.75 + 0.75 + 0.75) - T(0.5 + 0.1) = 0
2497.5 - 0.6T = 0
T = 4162.5 N
= 4.16 kN
Therefore, we can conclude that the tension in the rope if the frame is in equilibrium is 4.16 kN.