Answer:
electric field is 4.75 × 
V/m
Explanation:
given data
cube of side = 1 mm
energy = 10 J
to find out
magnitude of the electric field
solution
to find electric field
we will apply here energy formula that is
energy = 1/2 × ∈ × E² × volume ...............1
here we know ∈ = 8.85 × 
so put all value to get E electric field
energy = 1/2 × ∈ × E² × volume
10 = 1/2 × 8.85 × × E² × (1/1000)³
solve it and get E
E² = 2× 10 / 8.85 × × (1/1000)³
E = 4.75 ×
so electric field is 4.75 × V/m
Answer:
θ_c = 24.4º
Explanation:
To find the critical angle, let's use the law of refraction where index 1 refers to the incident medium (diamond) and index 2 refers to the medium where it is to be refracted (air)
n₁ sin θ₁ = n₂ sin θ₂
for the critical angle the ray comes out refracted parallel to the surface, therefore the angle is
θ₂ = 90
n₁ sin θ₁ = n₂
θ_c = θ₁ = sin⁻¹ 
the index of refraction of the diamond is tabulated
n₁ = 2.419
let's calculate
θ_c = sin⁻¹ (
)
θ_c = 24.4º
Answer:
7. 01 * 10^7 N/C
Explanation:
Parameters given:
Distance, y = 2.9 m
Radius, R = 2.9 cm = 0.029m
Charge, Q = 5.0 µC = 5 * 10^(-6) C
Given that:
E = 2πKσ(1- [y/(R² + y²)]) j^
Charge density, σ, is given as:
σ = Q/A = Q/πR²
=> E = 2πKQ/πR² (1- [y/(R² + y²)]) j^
E = 2KQ/R² (1 - [y/(R² + y²)]) j^
E = (2 * 9 * 10^9 * 5 * 10^(-6) / 0.029²) (1 - [2.9/(0.029² + 2.9²)]) j^
E = 107015.46 * 10^3 *(1 - 2.9/8.41) j^
E = 107015.46 * 10^3 * 0.655 j^
E = 7.01 * 10^7 j^ N/C
The magnitude of the electric field is 7.01 * 10^7 N/C. The j^ shows the direction.
Answer:187500m
Explanation:
frequency=1600kHz
Velocity=3x10^8 m/s
Wavelength=velocity ➗ frequency
Wavelength=(3x10^8) ➗ 1600
Wavelength=187500m
