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Annette [7]
4 years ago
7

A horizontal line above the time axis of a speed vs. time graph means an object is ___.

Physics
1 answer:
miv72 [106K]4 years ago
6 0
A horizontal line on a speed/time graph means a constant speed.
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A proton with a velocity in the positive x-direction enters a region where there is a uniform magnetic field B in the positive y
Gennadij [26K]

Answer:

Negative z-direction.

Explanation:

We need to determine the direction of the magnetic force. Since the velocity of the proton is in the positive x direction, and the magnetic field is in the positive y direction, we know by the vectorial formula F=q(v\times B) (or, alternatively, with the <em>left hand rule</em>) that the magnetic force points in the positive z-direction (also taking into account that <u>the charge is positive</u>), so the electric field should be in the negative z-direction to balance it.

5 0
4 years ago
A stone is placed in a graduated cylinder to determine its volume. The following data are obtained. What is the volume of the st
LUCKY_DIMON [66]
To solve this, you subtract the initial volume from the final volume. So, 29.5 mL minus 25.0 mL is 4.5 mL. Technically, at this point you need to say 4.50 mL, because of sig figs. The volume of the stone will not be in mL, because the stone is not a liquid or a gas, so you must convert it to cm3. So, your answer is (a), 4.50 cm3.
Hope this helps!
3 0
3 years ago
Read 2 more answers
A cannon fires a shell straight upward; 1.8 s after it is launched, the shell is moving upward with a speed of 17 m/s. Assuming
goblinko [34]

To solve this problem we will apply the concepts of acceleration according to the laws of kinetics. Acceleration can be defined as the change in velocity per unit time, that is,

a = \frac{v-u}{t}

Here,

v = Final velocity

u = Initial velocity

t = Time

Rearranging to find the initial velocity,

u = v-at

Now the acceleration is equal to the gravity, then,

u = v+gt

u = 17+(9.8)(1.8)

u = 34.64m/s

The velocity of the shell at 5.5s after the launch is,

v = u+at

v = u-gt

v = 34.64-(9.8)(5.5)

v = -19.26m/s

Therefore the magnitude of the velocity of the shell at 5.5s is -19.26m/s

5 0
3 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
Andrews [41]

Explanation:

It is given that,

Mass of the runner, m = 70 kg

Length of the tendon, l = 15 cm = 0.15 m

Area of cross section, A=110\ mm^2=0.00011\ m^2

Part A,

Let the runner's Achilles tendon stretch if the force on it is 8.0 times his weight, F = 8 mg

Young's modulus for tendon is, Y=0.15\times 10^{10}\ N/m^2

The formula of the Young modulus is given by :

Y=\dfrac{F/A}{\dfrac{\Delta L}{L}}

0.15\times 10^{10}=\dfrac{8\times 70\times 9.8/0.00011}{\dfrac{\Delta L}{0.15}}

\Delta L=0.0049\ m

Part B,

The fraction of the tendon's length does this correspond is given by :

\dfrac{\Delta L}{L}=\dfrac{0.0049}{0.15}

\dfrac{\Delta L}{L}=0.0326

Hence, this is the required solution.

6 0
3 years ago
A 7 kg object attached to a horizontal string moves with constant speed in a circle on a frictionless horizontal surface. The ki
Marizza181 [45]

Answer:

Explanation:

Given

mass of object m=7 kg

kinetic Energy k=36\ J

Tension in string T=326\ N

mass is moving in a horizontal circle so tension is providing the centripetal acceleration

therefore T=\frac{mv^2}{r}----1

where r=radius of circle

kinetic energy of particle k=\frac{1}{2}mv^2----2

divide 1 and 2 we get

\frac{T}{k}=\frac{\frac{mv^2}{r}}{\frac{1}{2}mv^2}

\frac{T}{k}=\frac{2}{r}

r=\frac{2k}{T}=\frac{2\times 36}{326}

r=0.2208\ m

   

8 0
3 years ago
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