Answer:
The length of the four pieces of protective strip is 96 feet
Step-by-step explanation:
Let the w be the width of the rectangular house and L is length. Since L = w + 16, its perimeter P = 2(w + L)
= 2(w + w + 16)
= 2(2w + 16)
Since the perimeter of the house P = 136 feet,
136 = 2(2w + 16)
dividing through by 2, we have
136/2 = (2w + 16)
68 = (2w + 16)
collecting like terms, we have
68 - 16 = 2w
52 = 2w
dividing through by 2, we have
w = 52/2
w = 26 feet.
Now, since the side walk is 3 foot wide all around, the width of the house plus sidewalk = w + 3 and the length of the house plus sidewalk = L + 3 = w + 16 + 3 = w + 19.
So, the perimeter of the house plus sidewalk which is the perimeter of the four pieces of protective strip is P' = 2(w + 3 + w + 19)
= 2(w + 22)
= 2(26 + 22)
= 2(48)
= 96 feet
So, the length of the four pieces of protective strip is 96 feet.
I just did it on paper but hope that helps:)
Answer:
Area of each piece = 104 
Possible dimensions are 26 cm by 4 cm, 13 cm by 8 cm.
Step-by-step explanation:
Given that:
Dimensions of the rectangular board as:
Length of the board is 10 cm longer than its width.
Width of the board = 26 cm
Length of the board = 26 + 10 = 36 cm
The rectangular board is divided into 9 equal pieces.
To find:
Area of each piece and
the possible dimensions of each piece = ?
Solution:
First of all, let us calculate the area of bigger rectangular board.
Area of a rectangle is given by the following formula:

Area = 26
36 
Area of each smaller rectangle = 
To find the possible dimensions, we need to find the factors of 104.
104 = 26
4
104 = 13
8
Therefore, the Possible dimensions are 26 cm by 4 cm
and
13 cm by 8 cm.