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ch4aika [34]
2 years ago
13

Your school football team wants to make a new banner to display at the district tournament. The rectangular banner will be dark

red, with a white ribbon border. The length of the banner needs to be 15 feet. What are the possible widths of the banner if the length of ribbon available is 46 feet?
Mathematics
2 answers:
bazaltina [42]2 years ago
7 0

Answer: Possible width of the banner would be 8 feet.

Step-by-step explanation:

Since we have given that

Length of the banner = 15 feet

Length of ribbon available = 46 feet

Since the banner is in the form of rectangle using dark red with white ribbon border.

So, perimeter of banner would be 46 feet.

As we know the formula for "Perimeter of rectangle":

Perimeter = 2( length + Breadth)

46=2(15+w)\\\\46=30+2w\\\\46-30=2w\\\\16=2w\\\\\dfrac{16}{2}=w\\\\w=8\ feet

Hence, Possible width of the banner would be 8 feet.

photoshop1234 [79]2 years ago
6 0
46 times 15= 690 if it's multiplying
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Question: What are the domain and range of the equation?
To find the range of the equation, we just transform the quadratic equation into the form y=a(x-h)^{2}+k. The value for k would be the maximum element in our range, and for the sake of the problem, let's assume that we don't have negative prices.

y=-0.092+0.587x-0.026x^{2}
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Question: Do you think your equation is a good fit for the data?
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