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notsponge [240]
3 years ago
12

Electric Charge andStatic ElectricityIt was known as early as 600BCEthat objects could become charged by rubbing fur on various

substances such as amber. Charged objects could be used to attract light objects such as hair. In the 1700s, it was determined that charge came in two varieties that could cancel each other out. Charles-Augustin de Coulomb established a quantitativerelation in 1783 that describes how charged objects interact via the electric force. The electric force:
Physics
1 answer:
Ulleksa [173]3 years ago
3 0

Answer:

Explanation:

In 1785, Coulomb investigated quantitatively, the force exerted between point charges.

The Coulomb's Law states that: "The force of attraction or repulsion between two, point charges is directly proportional to the product of magnitude of the charges and inversely proportional to the square of the distance between them. "

If q₁ and q₂ are two, point charges and r is the distance between them, then the electric force of attraction or repulsion F between them, according to Coulomb’s law will be:

F ∝ q₁q₂ ________________________ eqn (1)

F ∝ 1/r²  ________________________ eqn (2)

Combining eqn (1) and eqn (2), we get:

F ∝ (q₁ q₂)/r²  

<u>F = (kq₁q₂)/r²  </u>

where,

k = constant of proportionality = 9 x 10⁹ N.m² / C²

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n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

4 0
3 years ago
James is planning a science fair project on sound waves. He places an alarm inside a jar which he can remove the
otez555 [7]

Answer: c

Explanation:

Sound waves cannot travel through a medium

3 0
3 years ago
What is the definition of a neutron?
Fudgin [204]

Answer:

neutron is a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.

3 0
3 years ago
Read 2 more answers
If the value of static friction for a couch is 400N, what could be a possible value
miv72 [106K]

Answer:

kinetic friction may be greater than 400 N or smaller than 400 N

Explanation:

As we know that maximum value of static friction on the rough surface is known as limiting friction and the formula of this limiting friction is known as

F_s = \mu_s N

now when object is sliding on the rough surface then the friction force on that surface is known as kinetic friction and the formula of kinetic friction is known as

F_k = \mu_k N

now we know that

\mu_k < \mu_s

so here value of limiting static friction force is always more than kinetic friction

also we know that

initially when body is at rest then static friction value will lie from 0 N to maximum limiting friction

and hence kinetic friction may be greater than static friction or if the static friction is maximum limiting friction then kinetic friction is smaller than static friction

so kinetic friction may be greater than 400 N or smaller than 400 N

3 0
3 years ago
Three 15-Ω and two 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes thro
serious [3.7K]

Answer:

I = 0.25 A

Explanation:

Given that,

Three 15 ohms and two 25 ohms light bulbs and a 24 V battery are connected in a series circuit.

In series combination, the equivalent resistance is given by :

R=R_1+R_2+R_3+....

So,

R=15+15+15+25+25\\\\=95\ \Omega

The current each resistor remains the same in series combination. It can be calculated using Ohm's law i.e.

V = IR

I=\dfrac{V}{R}\\\\I=\dfrac{24}{95}\\\\I=0.25\ A

So, the current of 0.25 A passes through each bulb.

5 0
3 years ago
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