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Oxana [17]
4 years ago
13

When a third object is brought in contact with the first object (after it gains the electrons), the resulting charge on the thir

d object is 0.9 C. What was its initial charge (in C)?
Physics
1 answer:
nirvana33 [79]4 years ago
8 0

Answer:

- Contact 1 with 3 ,  initial charge of 1.8 C.

- contact 1 with 2 and then 1 with 3 , first body should have 3.6 C

Explanation:

The excess charge on a body is distributed evenly throughout the body.

We can have two different configurations:

- Contact 1 with 3

When the third body was touched with the first, the initial charge was distributed between the two, so that when each one separated, it had half the charge, in this configuration the first body should have an initial charge of 1.8 C.

- contact 1 with 2 and then 1 with 3

Another possible configuration of the exercise is that the first body touches the second and the charge decrease to the half and then touches the third where it again decreases by half, so that the first body only gives it every ¼ of its initial load.

Therefore in this configuration if the third body has a load of 0.9C the first body should have 3.6 C

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Answer:

The 2nd option

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3 years ago
Using the projectiles equations for y and x at what second does the ball have a vertical velocity of -39.2 m/s^2
vovangra [49]

Answer:

<h2>a) t = 4</h2>

Explanation:

In projectile the time taken by an object to reach its maximum height is the maximum time (tmax).

tmax = Usin\theta/g

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\theta = angle of projection = 90° (vertical velocity)

g = acceleration due to gravity = 9.8m/s²

tmax = Usin90°/9.8

tmax = U/9.8

T the maximum height U = Uy =  39.2 m/s²

tmax = 39.2/9.8

tmax = 4secs

To calculate the time at which the ball will have an horizontal velocity, we will use the same formula but \theta will be 0° in this case

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8 = Ucos0

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8 0
3 years ago
Motion and force of physics. Plz answer.​
Whitepunk [10]

Explanation:

a. " for every action there is an equal and opposite reaction".

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3 years ago
A glass ball of radius 3.74 cm sits at the bottom of a container of milk that has a density of 1.04 g/cm3. The normal force on t
Gelneren [198K]

Answer:

The mass of the ball is 0.23 kg

Explanation:

Given that

radius ,r= 3.74 cm

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The volume of the ball V

V=\dfrac{4}{3}\pi r^3

V=\dfrac{4}{3}\times \pi \times 3.74^3\ cm^3

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The bouncy force on the ball = Fb

Fb = ρ V g

Fb  + N = m g

m=Mass of the ball = Density x volume

m = γ V    , γ =Density of the Ball

ρ V g  + N =  γ V g               ( take g= 10 m/s²)

\gamma =\dfrac{N+\rho V g}{V g}

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5 0
3 years ago
A mass M is attached to a spring with spring constant k. When this system is set in motion with amplitude A, it has a period T.
labwork [276]

Answer:

T' = o.707T

Explanation:

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7 0
3 years ago
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