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Gre4nikov [31]
3 years ago
13

THX PLZ HELP choices that go to the attachment are, $64 $65 $67 $68

Mathematics
2 answers:
posledela3 years ago
8 0

Answer:

$64 is the answer

Step-by-step explanation:

If I am correct the x and y values are the ones values of the overall $60 so if you on the x axis to where the 6 is it matches up with the 4 on the y axis so therefore the answer must be $64.

I hope this helps

patriot [66]3 years ago
7 0

Answer:

$68

Step-by-step explanation:

Looking at the graph the coupon saved $2 consistently so you do $66+$2=$68

Can i get a brainliest?

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Solve the system of equation please help , I would greatly appreciate it
xz_007 [3.2K]

Answer: Your answer is going to be D. (10, -1)


Step-by-step explanation:

Starting off the equation you want to get rid of either x or y ( I did x first)

Take x+3y=7 and multiply the entire equation by -2 -- -2(x+3y=7)

You get -2x-6y=-14 and then add the two equations together

-2x-6y=-14

2x-4y=24  -- You get -10y = 10

y = -1

You can take the -1 and plug it back into either equation.. ( I did x+3y=7)

x+3(-1)=7 -- x-3=7 -- Add the 3 to get the 10 ( x = 10 )

So you have x = 10 & y = -1

(10,-1)




4 0
3 years ago
Read 2 more answers
WORTH 50 POINTS graph y=4/7x−2​. i need two points
Pachacha [2.7K]
Cant really show you how to do it but the graph would start at the y axis at (0,-2) then from there each point would move to the left 4 and up 7 or back 4 and down 7. It would form a straight line.
3 0
2 years ago
How do I solve this?
FinnZ [79.3K]
(12 + 2v + 13v^3) + (13v^3 + 7 + 7v)
12 + 2v + 13v^3 + 13v^3 + 7 + 7v - drop the parenthesis since adding
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4 0
3 years ago
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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
2 years ago
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GIVING BRAINLIEST FOR BEST ANSWER!
ra1l [238]

Answer:

its B

Step-by-step explanation:

Hope it helps

7 0
2 years ago
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