The approximate acceleration of the car would be <span>3.00
</span>How? We have to use the formula to find the velocity.
v = d/t = 120/6.32
v = 19
Then plug the factor into the acceleration formula to find the acceleration:
a = v/t = 19/6.32
a = 3.00
So, the approximate acceleration of the car would be 3.00
Answer:
Explanation:
Let the initial speed be u . final speed = 0
v² = u² - 2gh
v is final speed , u is initial speed , h is height .
0 = u² - 2g x 134
u² = 2 x 9.8 x 134
u = 51.25 m /s .
Answer:
a.6533.333 N/m
b.Yes,the spring will be compressed more when the person hops down the road .
Explanation:
Mass of man=80 kg
Spring compressed by x=0.12 m
a.We have to find the force constant of the spring.
Spring constant=

Using the formula
Spring constant,
N/m
Spring constant=
b.The spring will be compressed more when the person hops down the road because when the person hops down then the kinetic energy of person will be converted into potential energy during the road hit.
Answer:
the less shielding of electrons
Increasing the level of an incline:
Increases final velocity
Increases the work done
Increases the initial potential energy
Increases the final kinetic energy