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nika2105 [10]
3 years ago
13

What is a type of pulley that increases the size and effort of force

Physics
1 answer:
12345 [234]3 years ago
5 0
The answer is Movable
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A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane
Mama L [17]

Answer:

Magnetic field, B = 0.199 T

Explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop, \phi=8.6\times 10^{-3}\ T/m^2

The magnetic flux linked through the loop is :

\phi=B.A

\phi=BA\ cos\theta

Here, \theta=0

B=\dfrac{\phi}{A}

or

B=\dfrac{\phi}{\pi r^2}

B=\dfrac{8.6\times 10^{-3}}{\pi (0.117 )^2}

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.

4 0
3 years ago
A ray of light in air is incident on the mid-point of a heavy flint glass prism surface at an angle of 20º with the normal. for
Nata [24]
Assuming that you have a triangular prism, the ray of light will undergo refraction twice. The first time is the transition from air to flint glass on the entry face, and the second time is the transition from the flint glass to air from the exit face. With the available data, there are two possible solution since saying "20Âş from the normal" isn't enough information. Depending upon which side of the normal that 20 degrees is, the interior triangle will have the angles of 35, 90-r, and 55+r, or 35, 90+r, 55-r degrees where r is the angle from the normal after the 1st refraction. I will provide both possible solutions and you'll need to actually select the correct one based upon the actual geometry which I don't know because you didn't provide the figure or diagram that you were provided with.    

The equation for refraction is:  

(sin a1)/(sin a2) = n1/n2  

where  

a1,a2 = angles from the normal to the surface.  

n1,n2 = index of refraction for the transmission mediums.    

For this problem, we've been given an a1 of 20Âş and an n1 of 1.60. For n2, we will use air which at STP has an index of refraction of 1.00029. So  

(sin a1)/(sin a2) = n1/n2  

(sin 20)/(sin a2) = 1.00029/1.60  

0.342020143/(sin a2) = 0.62518125  

0.342020143 = 0.62518125(sin a2)  

0.547073578 = sin a2  

asin(0.547073578) = a2  

33.16647891 = a2    

So the angle from the normal INSIDE the prism is 33.2Âş. The resulting angle from the surface of the entry face will be either 90-33.2 or 90+33.2 depending upon the geometry. So the 2 possible triangles will be either 35Âş, 56.8Âş, 88.2Âş or 35Âş, 123.2Âş, 21.8Âş. with a resulting angle from the normal of either 1.8Âş or 68.2Âş. I can't tell you which one is correct since you didn't tell me which side of the normal the incoming ray came from. So let's calculate both possible exits.    

1.8Âş  

(sin a1)/(sin a2) = n1/n2  

(sin 1.8)/(sin a2) = 1.6/1.00029  

0.031410759/(sin a2) = 1.599536135  

0.031410759= 1.599536135(sin a2)  

0.019637418= sin(a2)  

asin(0.019637418) = a2  

1.125213477 = a2    

68.2Âş  

(sin a1)/(sin a2) = n1/n2  

(sin 68.2)/(sin a2) = 1.6/1.00029  

0.928485827/(sin a2) = 1.599536135  

0.928485827 = 1.599536135(sin a2)  

0.58047193 = sin a2 

 asin(0.58047193) = a2 

 35.48374252 = a2   

 So if the interior triangle is acute, the answer is 1.13Âş and if the interior triangle is obtuse, the answer is 35.48Âş
5 0
3 years ago
The Doppler shift may be helpful for someone trying to _______. overcome a visual illusion block out irrelevant noises locate so
mestny [16]

Answer:

The Doppler shift may be helpful to determine the relative speed of an object by bouncing a wave (usually a radar wave) off the object and measuring the shift in the frequency of the wave.

Explanation:

Doppler shift helps to overcome a visual illusion block out irrelevant noises, locate sounds and see an object in very dim light by determining the relative speed of an object by bouncing a wave

8 0
3 years ago
PLZZZ HELP
matrenka [14]

B. A sandbar is formed by water. A sand dune is formed by wind.

4 0
3 years ago
which phrase best defines erosion. chemically breaking rocks apart, moving bits of rock from place to place , cementing bits of
mina [271]
Physically breaking rocks apart i think
i hope this helps
4 0
3 years ago
Read 2 more answers
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