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3 years ago

Multiply. Express each answer as a decimal. 12⋅15 34⋅200 (0.2)⋅60 (0.75)⋅20

Mathematics

1 answer:

katovenus [111]3 years ago

3 0

Answer:

12×15=180
34×200=6800
(0.2)×60=12
(0.75)×20=15

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Ricky is filling an 8 inch by 4 inch by 4 1/2 inch rectangular box with packing peanuts. The peanuts are cubes that come in two

RideAnS [48]

First find the volume of the box: 8•4•4.5=144 cubic inches.
8 of the 1/8 inch=1 of the 1 cubic inch
He could do 144 and 0
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Or just keep following the pattern... Hope that helped

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2 years ago

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kirza4 [7]

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2 years ago

Rewrite this non-statistical question as a statistical question. How many minutes do I exercise each day?

stira [4]

Answer:

The statistical question should be

"how many minutes do I exercise on each day of the week" and "how many minutes do I exercise each day of the week whilst there is background music"

Step-by-step explanation:

Here we have the non statistical question, how many minutes do I exercise each day

We note that a statistical question is one in which there are are different variety answers, where the distribution and the inclination of the the answers is sought

Therefore, statistically, we should ask, "how many minutes do I exercise on each day of the week" or "how many minutes do I exercise each day of the week whilst there is background music".

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3 years ago

Which is greater, the total length of the1/8 -inch tadpoles or the total length of the 1/4 -inch tadpoles?

Karolina [17]

Answer:

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Step-by-step explanation:

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2 years ago

25. Michael is studying population changes in two

g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

Average Rate of Change

Bird A:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{9.1 - 8.3}{18 - 0}$

Average = 0.045

Bird B: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{68.7 - 0}{18 - 0}$

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

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2 years ago