Question

Two astronauts, connected by a massless cord of length 10 m, sit motionless in deep space. The astronaut masses are ????1 = 60 kg and ????2 = 100 kg. The astronaut with mass ????1 catches a package of mass m = 20 kg tossed to him from the left with a velocity v = 2 m/s. Treat the astronauts as if they are point masses. (a) (5 points) The final system rotates about the center of mass of the system. What is yC????? Take y=0 to be the position of the top astronaut.

Answer 1

Answer:

Explanation:

Let masses of astronaut be m₁  = 60 kg and m₂ = 100 kg

m₁ is at y₁ = 0 and m₂ is at y₂ = - 10 m

We have to find center of mass .

Ycm = m₁y₁ +  m₂y₂ / ( m₁ + m₂ )  ,

Ycm = m₁ x 0 +  100 x -10 / ( 60 + 100 )

= $\frac{-1000 }{160}$ m

= - 6.25 m .

center of mass y = - 6.25 m .