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hoa [83]
3 years ago
15

Which of the following statements about planetary satellites is true? all planetary satellites are as large as our moon or bigge

r. all planetary satellites are relatively small, typically having a radius of no more than 20 kilometers. planetary satellites vary greatly in size, but none are larger than any of the planets in the solar system. planetary satellites vary greatly in size, from very small, to some that are larger than some planets.
Physics
2 answers:
Illusion [34]3 years ago
6 0
<span> planetary satellites vary greatly in size, from very small, to some that are larger than some planets.</span>
Anvisha [2.4K]3 years ago
3 0

Answer:

Planetary satellites vary greatly in size, from very small, to some that are larger than some planets.

Explanation:

Natural sateletes are celestial bodies that orbit other larger celestial bodies. The solar system has several satellites, the best known being the moon, the natural satellite of planet Earth. The planets of the solar system have different sizes, just like the natural satellites. Thus, there are satellites larger than planets. The moon itself is a larger satellite than some planets, like Mercury.

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What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?
sveta [45]
Momentum = (mv). 
<span>(2110 x 24) = 50,640kg/m/sec. truck momentum. </span>
<span>Velocity required for car of 1330kg to equal = (50,640/1330), = 38m/sec</span>
8 0
3 years ago
When you whisper you produce a 10-dB sound.
masha68 [24]
All you would do is for a, 10 times 2 is 20 so it would be 20-dB 
For b, 10 times 4 is 40 so it would be 40-dB
<span>For c, 10 times 8 is 80 so it would be 80-dB</span>
4 0
3 years ago
A shopping cart given an initial velocity of 2.0 m/s north undergoes a constant acceleration of 3.0 m/s2 north. what is the dist
morpeh [17]

Following the initial 4.0 seconds of travel, the cart moved 32m.

<h3>What is an equation of motion?</h3>

Physicists use equations of motion to describe how a physical system behaves in terms of how its motion changes over time.

The behavior of a physical system is described by the equations of motion in more detail as a collection of mathematical functions expressed in terms of dynamic variables. These variables typically comprise time and spatial coordinates, but they could also have momentum components. The most flexible option is generalized coordinates, which can be any useful variable that is a component of the physical system. In classical mechanics, the functions are defined in a Euclidean space, while curved spaces are used in relativity instead. The equations are the answers to the differential equations describing the motion of the dynamics of the dynamics of a system are known. The amount of motion changes according to the strength of the force and does so in the direction of the force's applied straight line.

To know more about equations of motion, click here:

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7 0
2 years ago
Distinguish between contact force and non-contact forces give three examples of each
Artist 52 [7]

Answer:

1. the force which can be felt or act only when two objects are in contact is known as contact force.

for example: frictional force, muscular force,

tension, air resistance .

2. the force which can be felt or act even when two objects are in contact or not is known as non-contact force.

for example: magnetic force, gravitational force, electrostatic force.

6 0
3 years ago
The density of mobile electrons in copper metal is 8.4 1028 m-3. Suppose that i = 4.6 1018 electrons/s are drifting through a co
Vesna [10]

Answer:

The time is 106.7 minute.

Explanation:

Given that,

Density = 8.4\times10^{28}\ m^3

Current i = 4.6\times10^{18}\ electron/s

Diameter of wire = 1.2 mm

Length = 31 cm

We need to calculate the drift velocity

Using formula of drift velocity

v_{d}=\dfrac{I}{neA}

v_{d}=\dfrac{Ne}{tne\times\pi r^2}

Put the value into the formula

v_{d}=\dfrac{4.6\times10^{18}}{8.4\times10^{28}\times\pi\times(0.6\times10^{-3})^2}

v_{d}=4.842\times10^{-5}\ m/s

We need to calculate the time

Using formula for time

v_{d}=\dfrac{l}{t}

t=\dfrac{l}{v_{d}}

Where, l = length

v_{d} = drift velocity

Put the value into the formula

t=\dfrac{31\times10^{-2}}{4.842\times10^{-5}}

t=6402.31\ sec

t=106.7\ minute

Hence, The time is 106.7 minute.

7 0
3 years ago
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