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3 years ago

As the cross-sectional area of a conductor increases, its resistance .

Physics

2 answers:

n200080 [17]3 years ago

8 0

Answer:

Yess it’s resistance

Explanation:

Reptile [31]3 years ago

8 0

Answer:

DECRAAAASESSSS

Explanation:

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An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-

kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle $(m_1)=3\times 10^{-28} kg$

mass of heavier Particle $(m_2)=1.51\times 10^{-27} kg$

speed of lighter particle $(v_1)=0.834 c$

Let speed of heavier particle $=v_2$

and Momentum of the particle is given by

$P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}$

$P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}$

$P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}$

$P_1=8.219\times 10^{-28} kg c$

$P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

as momentum is conserved therefore $P_1=P_2$

$8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

$v_2=0.478 c$

3 0

3 years ago

Two people are talking through a thick wall, 3 meters high, between them. This fact can best be explained by the phenomenon of A

dezoksy [38]

The answer is Ai just took it

6 0

3 years ago

To tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.50•10^6 N, one at an angle 19.0° west of north, a

irina1246 [14]

Answer:

Work done by a tug boat, W = 1.735 x 10⁸ J

Explanation:

Given,

The of each tugboat, F = 1.5 x 10⁶ N

The angle of each tugboat forms with the resultant force, θ = 19°

The displacement of the supertanker, s = 710 m

The individual tugboat will be responsible for the displacement, d = 710/2

= 355 m

The displacement component in each tugboat direction = 355 · sin θ meter

Therefore, the work done by each tugboat is

W = F x S joules

Substituting the values in the above equation

W = 1.5 x 10⁶ x 355 · sin θ

= 1.735 x 10⁸ J

Hence, the work done by each tugboat is, W = 1.735 x 10⁸ J

6 0

3 years ago

Hey guys, I have a question about heat and stuff, and converting. THINK YOU COULD HELP?! THANKS!

Alexxandr [17]

Before answering this question it is necessary to know the conversion factors for temperatures.

273 k = 0 ° C

To transform a temperature from Kelvin to ° C we use the following Formula

T ° C = T Kelvin - 273

For 373 K

373K -273 = 100 ° C

373 Kelvin equals 100° C.

To transform a temperature from ° C to ° F we use the following formula:

(T° C x 9/5) + 32 = T ° F

Then:

For 0 ° C

(0° C x 9/5) +32 = 32 ° F

0° C equals 32 ° F.

For 100° C

(100 ° C x 9/5) +32 = 212 F

100 ° C equals 212 ° F.

Therefore, the correct option is the first:

373 Kelvin = 100 ° C = 212 ° F

4 0

3 years ago

The doppler effect is used to determine?

Korolek [52]

Uhh it is used to detirmine heat

7 0

3 years ago

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