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yuradex [85]
2 years ago
9

A number added to one- third of itself is 12 . What is the number​

Mathematics
1 answer:
Naya [18.7K]2 years ago
5 0

Answer:

it's 9

Step-by-step explanation:

i dont know how to explain

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Kairi spent $40.18 on CDs. Each CD cost the same amount. The sale tax was$2.33. Kairi also used a coupon for $1.00 off his purch
Arte-miy333 [17]

Therefore the cost of each CD is =$2.30

Step-by-step explanation:

Given , Kairi spent $40 .18 no CDs. The sale tax was $2.33.Kairi also used a coupon for $1.00 0ff his purchase.

Total cost price of The CDs is = $(40+2.33-1.00)

                                                =$41.33

Therefore the cost of each CD is =$(41.33÷18)

                                                       =$2.30

8 0
3 years ago
F = 0.272727... <br> 100f = (100) (0.272727...) <br> 100f = ?
olya-2409 [2.1K]
100f = 27.272727.....
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3 years ago
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I'm making a table.
Ivenika [448]
Well I think I can help you out ...
if you assume input x=2
the output will be as following :
y= -1/3(2)+2
=-2/3+2
=-2/3+6/3
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3 0
3 years ago
PLEASE HELP ASAP This table represents the monthly fees for checking accounts at two banks. Which statement is best supported by
Savatey [412]

a is the answer i took the test

7 0
3 years ago
Neal opened a savings account 11 years ago with a deposit of $2,335.69. The account has an interest rate of 4.3% compounded dail
Vinvika [58]

Answer: $1,412.52

Step-by-step explanation:

Formula to calculate the accumulated amount if <em>P</em> principal invested for <em>t </em>years at a rate of interest <em>r</em> that compounded daily is given by:-

A=P(1+\dfrac{r}{365})^{365t}

Given: P= $2,335.69

r= 4.3%= 0.043

t= 11 years

Then,

A=2335.69(1+\dfrac{0.043}{365})^{365\times11}\\\\=2335.69(1+0.000117808219178)^{4015}\\\\=2335.69(1.000117808219178)^{4015}\\\\= 2335.69(1.6047566747)\\\\=3748.09044309\approx3748.21\\\\\Rightarrow\ A=\$3748.21

Interest earned = A-P

= $3748.21- 2335.69.

= $1412.52

Hence, Neal earned $1,412.52 as interest.

8 0
3 years ago
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