:(((( i can't get this one! Please help...

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

6 0

Answer:

4877 fish

Step-by-step explanation:

Each year, the fish population is multiplied by 1-6% = 0.94, so after 8 years it has been multiplied by 0.94^8 ≈ 0.609569.

At that time, the population is ...

8000×0.609569 ≈ 4877 . . . fish

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George is helping the manager of the local produce market expand her business by distributing flyers

spin [16.1K]

Answer:

20 + 0.05x ≥ 65

Step-by-step explanation:

20 is by itself since thats what he earns extra per day.

Since he earns 0.05 per flyer, that means we are going to need a variable since we don't know how many flyers he passes. Let x be equal to that.

Since he wants to make at LEAST 65 we are going to use the greater than or equal to symbol since he doesn't want to make less than that.

20 + 0.05x ≥ 65

Best of Luck!

4 0

3 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

2 years ago

8x-2=4+5x<br><br> Solve for x

DochEvi [55]

$8x-2=4+5x\ \ \ |add\ 2\ to\ both\ sides\\8x=6+5x\ \ \ \ |subtract\ 5x]\ from\ both\ sides\\3x=6\ \ \ \ |divide\ both\ sides\ by\ 3\\\boxed{x=2}$